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Advocard [28]
2 years ago
11

Find the sum. Write your answer in standard form. (2x3+4x2+3)+(3x3−3x−4)

Mathematics
2 answers:
kvv77 [185]2 years ago
6 0

Answer:

5x³ + 4x² - 3x - 1

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

(2x³ + 4x² + 3) + (3x³ - 3x - 4)

<u>Step 2: Simplify</u>

  1. Combine like terms:                                                                                         5x³ + 4x² - 3x - 1
Neporo4naja [7]2 years ago
6 0

Answer:

3.8*10^1

Step-by-step explanation:

So we'll be using PEMDAS, which is an acronym used to explain order of operations. It stands for P- Parentheses, E- Exponents, M- Multiplication, D- Division, A- Addition, and S- Subtraction.

P- Parentheses:

(2x3+4x2+3)+(3x3−(3x−4))

M- Multiplication (within Parentheses):

(6+8+3)+(9−(-12))

A- Addition (within Parentheses):

(6+8+3)+(9−(-12))

17 + 21

A- Addition:

38

Now, we'll take that number and put it in standard form, which is the number with only one number outside of the decimal times ten to the however many times it can be divided by ten.

So,

38/10 = 3.8

So,

3.8 * 10^1 is your answer.

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Answer:

The Point estimate of the Population proportion  E = 0.039≅0.04

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the sample size 'n' = 992

  and                                     x = 570

The Population proportion

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6 0
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Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.
Mkey [24]

Answer:

1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}

Simplification takes place in the following manner:

a)

(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}

b)

(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}

c)

(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8

d)

(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}

4 0
3 years ago
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