Answer:
Unbounded, infinite number of solutions
Step-by-step explanation:
1. Graph each inequality separately
2. Choose test point to determine which side of line needs to be shaded
3. The solution will be the the area where the shadings from both inequalities overlap
Since, the overlap almost covers the 2nd and 3rd quadrants there are an infintite number of solutions
F(X) = 6/X
F(X) = 6 • 1/X
F(X) = 6 • x^-1
F(X) = 6x^-1
F'(X) = 6 • d(x^-1)/dx
F'(X) = 6 • -1x^-1-1
F'(X) = 6 • -1x^-2
F'(X) = -6x^-2
F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2
The solution would be C. -3/2.
The answer is 6 and that’s after it’s rounded