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3 years ago

Write an algebraic expression with the constant 7 and the variable y

1 answer:

6 0

Here are a few algebraic expressions that include
the constant ' 7 ' and the variable 'y' :

7y

2y + 7

(y + 3) · (y - 7)

7 sin(y)

7x² +43z - 0.1y

√7 / y

19 y⁷

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Please help I will give Brainliest please!

WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but $x \ne 0$ </h3>

To write this in interval notation, we can say $(-\infty, 0) \cup (0, \infty)$ which is the result of poking a hole at 0 on the real number line.

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The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say $(-\infty, \infty)$ which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation $x = \pm 4$

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer: Oblique asymptote is y = 3x</h3>

5 0

3 years ago

If you have a decimal answer, round to the nearest tenth!<br> 2/3c−4=8

Alenkasestr [34]

Answer:

= 18

Step-by-step explanation:

7 0

3 years ago

B(n)=-1(2)n-1 what's the 5th term in the sequence

Katena32 [7]

B5 = -1 x (2 ^ 5 - 1)
B5 = -1 x (2 ^ 4)
B5 = -1 x 16
B5 = -16

8 0

3 years ago

Kim's weekly pay is two thirds of Alicia's.Together they earn $600 per week

garik1379 [7]

A + k = 600
k = 2/3a

a + 2/3a = 600
3/3a + 2/3a = 600
5/3a = 600
a = 600 * 3/5
a = 1800/5
a = 360

k = 2/3a
k = 2/3(360)
k = 720/3
k = 240

so Kim's pay is $ 240 and Alicia's pay is $ 360

7 0

3 years ago

What are the answers?

LUCKY_DIMON [66]

<span>Podemos resolver as equações da seguinte forma:

11) -2,6 x 10³ ----> iremos andar três casas para direita.
X = -2600

12) 5,824 x </span> $10^{-2}$ <span> ---> iremos andar duas casas para esquerda.
X = 0,05824

13) - 5,408 ---> iremos adicionar o </span> $10^{0}$ <span>
x = </span> - 5,408 x $10^{0}$ <span>

14) 0,00907 ----> iremos adicionar o </span> $10^{-3}$
x = 9,07 x $10^{-3}$

Espero ter ajudado :)

3 0

3 years ago