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Jlenok [28]
2 years ago
10

Find the radius y of circle C, given that x = 12 and z = y + 8. PLEASEEE HELP ME

Mathematics
1 answer:
myrzilka [38]2 years ago
6 0
I think the answer is 3 :))
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What is the area of the figure? <br> A) 18 yd2 <br> B) 54 yd2 <br> C) 72 yd2 <br> D) 90 yd2
den301095 [7]

Answer:

<em><u>7</u></em><em><u>2</u></em><em><u> </u></em><em><u>yd²</u></em>

Step-by-step explanation:

area of this figure = area of 1st rectangle + area of 2nd rectangle

= l×b + L×B

= 6 × 5 + 14 × 3

=30 + 42

= 72 yd²

4 0
2 years ago
Can someone help please​
Jlenok [28]

Answer:

11/8 or, 1 and 3/8

Step-by-step explanation:

First, we have to make both the denominators the same. In this case, we can multiply 3/4 by 2, to make 4, the denominator, into 8. What we do to the denominator, we must do to the numerator! So, we multiply 3 by 2, and get 6!

Now we have, 5/8 + 6/8, which equals 11/8! Which can also be simplified to 1 and 3/8 (because the numerator is larger than the denominator)

Hope this helps! :)

5 0
3 years ago
An inverse variation function has a k value of 8. Which ordered pair is on the graph of the function?
Vinvika [58]

The points on the graph of the inverse variation are of the form:

(x, 8/x)

<h3>Which ordered pairs are on the graph of the function?</h3>

An inverse variation function is written as:

y = k/x.

Here we know that k = 8.

y = 8/x

Then the points (x, y) on the graph of the function are of the form:

(x, 8/x).

So evaluating in different values of x, we can get different points on the graph:

  • if x = 1, the point is (1, 8)
  • if x = 2, the point is (2, 4)
  • if x = 3, the point is (3, 8/3)
  • if x = 4, the point is (4, 2)

And so on.

If you want to learn more about inverse variations:

brainly.com/question/6499629

#SPJ1

7 0
1 year ago
Find the equation of the parabola that passes through
valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}

well, from the 1st  equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b

well, now let's plug that "b" into our 3rd equation and solve for "a".

\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill

3 0
3 years ago
Homework Progress
Alborosie
I think answer should be c. Please give me brainlest let me know if it’s correct or not okay thanks bye
7 0
3 years ago
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