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maks197457 [2]
3 years ago
10

The problem of (-1)(-1)(-1) would be negative True or False

Mathematics
2 answers:
prohojiy [21]3 years ago
6 0

Answer:

true

Step-by-step explanation:

qwelly [4]3 years ago
4 0

Answer:

True

Step-by-step explanation:

There are an odd number of negative signs (3)

If there is an odd number it is negative, but if it is even then the result will be positive

Here's a deeper explanation

-1 times -1 is simply 1

Then 1 times -1 is -1

Our final answer is -1 so this is true.

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Last year a computer was $350. The computer company raise prices this year and the price has increased by 5%. What was the price
Juliette [100K]

Answer:

367.5

Step-by-step explanation:

5% of 350 is 17.5

$350+$17.5=367.5

6 0
3 years ago
What is the next term of the geometric sequence?<br> 40 20 10<br> 27' 9'3?
Karo-lina-s [1.5K]
5 and 1
10/2=5 3/3=1
8 0
2 years ago
What is the slope of y=−12?
il63 [147K]

Answer:

the slope is 0

Step-by-step explanation:

6 0
3 years ago
casey is six time as old as Ralph, In two years, she will be four time as old as Ralph. How old is each of them now?
Keith_Richards [23]

Casey is 18 years old and Ralph is 3 years old.

Step-by-step explanation:

Let,

Age of Casey = x

Age of Ralph = y

According to given statement;

x = 6y     Eqn 1

In two years

x+2=4(y+2)

x+2=4y+8

x = 4y+8-2

x = 4y+6     Eqn 2

Putting value of x from Eqn 1 in Eqn 2

6y=4y+6 \\6y-4y=6\\2y=6

Dividing both sides by 2

\frac{2y}{2}=\frac{6}{2}\\y=3

Putting y=3 in Eqn 1

x=6(3)\\x=18

Casey is 18 years old and Ralph is 3 years old.

Keywords: word problems, substitution method

Learn more about substitution method at:

  • brainly.com/question/12973601
  • brainly.com/question/13063819

#LearnwithBrainly

7 0
3 years ago
1-116 1.2.6
ankoles [38]

Answer:

A. 30 adults; B. 24 not dolls

Step-by-step explanation:

A.

\begin{array}{rcl}\text{No. of adults} & = & \text{No. of visitors} \times \text{Fraction who are adults}\\& = & \text{100 visitors} \times \dfrac{\text{3 adults}}{\text{10 visitors}} \\& = & \textbf{30 adults}\\\end{array}

B.

If five-eighths of the prizes were dolls, then three-eighths of the prizes were not dolls.

\begin{array}{rcl}\text{No. not dolls} & = & \text{No. of prizes} \times \text{Fraction not dolls}\\& = & \text{64 prizes} \times \dfrac{\text{3 not dolls}}{\text{8 prizes}} \\& = & \textbf{24 not dolls}\\\end{array}

3 0
3 years ago
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