1/2 y +6 = x
y=2 (x-6)
= 2x-12
f^-1 (x)= 2x-12
We know that
in a right triangle
cos θ=adjacent side angle <span>θ/hypotenuse
in this problem
</span>adjacent side angle θ=38 in
hypotenuse=40 in
cos θ=38/40
θ=arc cos (38/40)-------> 18.19°-------> 18°
the answer is
18 degrees
Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>