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ivolga24 [154]
3 years ago
13

Solve for x. please show work

Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0
Those 2 angles makes up corresponding angles in parallel lines. Which means, both two angles equal to each other because this is a rule that exists when both of the lines are parallel to each other which is indicated with red arrows in the photo.
75 = 11x - 2
75 + 2 = 11x
77 = 11x
X = 77 / 11
X = 7
The answer is 7.
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serious [3.7K]

can you show me a picture then maybe i can help you

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3 years ago
Asif spent $745.10 on 13 new file cabinets for his office. Small file cabinets cost $43.50 and large file cabinets cost $65.95.
pentagon [3]

Answer:


Step-by-step explanation

<h2></h2>
6 0
3 years ago
If A={2,3,5,7} and B={2,4,6,8} then what is AnB?​
gregori [183]

Answer:

  • A∩B = {2}

Step-by-step explanation:

It asks for the common set of A and B.

<u>There only one element common to both the given sets:</u>

  • A={2,3,5,7} and B={2,4,6,8} ⇒ A∩B = {2}
6 0
3 years ago
Read 2 more answers
The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar
o-na [289]

The length of each side of the larger square is 8 cm.

<u>Step-by-step explanation</u>:

Step 1 ;

  • The combined area of two squares = 80 sq.cm
  • The side of small square = x
  • The side of larger square = 2x

Step 2 :

Area of the square = a^2

Area of small square + area of large square = 80

x^2 + (2x)^2 = 80

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 80/5

x^2 = 16

x = ±4

Step 3 :

Since length cannot be negative, the value of x= 4

∴ The length of the side of small square = 4cm

The length of the side of larger square = 2x = 8cm

5 0
3 years ago
I am being timed. Please help
baherus [9]

Answer:

It would be 8 PM.

Step-by-step explanation:

If you keep decreasing 23 by 7 till you get to -5, it would have to be decreased 4 times to get to -5. This means that the time would have to go up 4 times the 45 minute rate, which would be 3 hours. 5 pm + 3 hours is 8 PM.

5 0
3 years ago
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