1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dmitriy555 [2]
3 years ago
7

Stephen was disappointed in his grade on a recent statistics test. He calculated his 2-score and found that it was 0.45. What pe

rcent of students scored below Stephen's score?​
Mathematics
1 answer:
grin007 [14]3 years ago
7 0
I would say 2 because it says he calculated his 2- score.
You might be interested in
The price of petrol increased from Rs 48 to rs 53.76.
mylen [45]

Answer:

12%

Step-by-step explanation:

As per the provided information in the given question, we have :

  • Original price of petrol = Rs. 48
  • New price of petrol = Rs. 53.76

We are asked to calculate,

  • Percentage increase

As we know that,

\\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{Price \; increase}{Original \; price} \times 100 \Bigg ) \; \%}} \\

→ Price increase = New price - Original price

→ Price increase = Rs. ( 53.76 - 48 )

→ Price increase = Rs. 5.76

Substituting values,

\\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{5.76}{48} \times 100 \Bigg ) \; \%}} \\

\\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{576}{4800} \times 100 \Bigg ) \; \%}} \\

\\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{57600}{4800} \Bigg ) \; \%}} \\

\\ \longrightarrow \sf{\quad { \% \; increase =\Bigg ( \dfrac{576}{48} \Bigg ) \; \%}} \\

\\ \longrightarrow \bf{\quad\underline { \% \; increase = 12\; \%}} \\

<u>There</u><u>fore</u><u>,</u><u> </u><u>percen</u><u>tage</u><u> </u><u>incre</u><u>ase</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u> </u><u>%</u><u>.</u>

4 0
3 years ago
Jamal used 7.56 liters of milk to make milkshakes for him and 11 friends. Each milkshake used the same amount of milk. How much
kirill115 [55]

Answer:

0.63 Liters, or, if needed in fraction form, about 2/3 of a Liter per milkshake

Step-by-step explanation:

7.56 liters in total /divided by 11(+1 for Jamal) friends/ = ).63 liters per shake

8 0
3 years ago
What’s the answer to: <br><br> 2x+2 + 4x-4
blsea [12.9K]
6x-2. Which can be simplified to (3x-1) by taking a common factor, 2.
4 0
3 years ago
Read 2 more answers
Find the missing side. round to the nearest tenth
barxatty [35]
So you would use the law of sines so set up the equation sin18/16 = sin72/x (sin 72 being the top angle) and then you cross multiply and solve from there:)
Hope this helps!
3 0
3 years ago
Read 2 more answers
The sum of the following geometric series.<br> 7-56+448-3,584+... when n=11
faust18 [17]

Answer:

A. 6.681.060.239

Step-by-step explanation:

a1 = 7

r = (-8)

n= 11

S11 = 7((-8)^11 - 1)/ (-8-1)

= -7/9 ( -8,589,934,591)

= 6.681.060.239

6 0
3 years ago
Other questions:
  • The mean of the following data values is 32. <br> 19, 23, 35, 41, 42<br> A. True <br> B. False
    10·1 answer
  • Each of the triangular faces has an area of 32 m2.
    9·1 answer
  • 3 eggs and 2 cups of sugar to make 30 cookies. How many eggs and cups of sugar do you need to make 50 cookies
    9·2 answers
  • ? I'm not to sure of this answer
    13·1 answer
  • If f(x)=1/9x-2, what is f-1(x)
    13·1 answer
  • Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
    14·1 answer
  • Murray Hill Middle School has 800 students. If 65% of the students ride the bus to school, then how many students ride the bus t
    7·2 answers
  • Can somebody also help with this? Sorry I just don't comprehend word problems<br>​
    13·2 answers
  • PLEASE HELP i have been on this question forever
    7·2 answers
  • The following diagram represents all of the stages of a shrinking iceberg. The iceberg is circular, and when it started out, it
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!