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3 years ago

I will give this much points for 7 (x+5)

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:7x+35

Step-by-step explanation:

amid [387]3 years ago

4 0

Answer:

7x+35

Step-by-step explanation:

7(x+5)

=(7)(x+5)

=(7)(x)+(7)(5)

=7x+35

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Find the volume of a cone when given height and circumference.

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Step-by-step explanation:

V = π ∙ r2 ∙ h / 3, where π ∙ r2 is the base area of the cone. π defines the ratio of any circle's circumference to its diameter and is approximately equal to 3.141593, however the value 3.14 is often used. Example 1: Find the volume of cone, whose radius is 8 cm and height is 5 cm.

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3 years ago

Ms.Jackson went to the local market to buy 50 pieces of fruit. Out of the 50 pieces of fruit she bought, 14 were apples. What fr

harkovskaia [24]

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3 years ago

Read 2 more answers

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$

Observe that, because $n \geq 2$ and is an integer,

$n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5$

In concusion, the statement is true if and only if n is a non negative integer such that $n\leq 77$

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute $(4n)^4- \sum^{n}_{i=0} (2i)^4$ for 77 and 78 you will obtain:

$(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064$

$(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992$

7 0

3 years ago

The product of three integers is-3 Determine all of the possible values for the three factors

miskamm [114]

3 * 1 * -1 because 3 times one is 3 and that times a negative turns it into a negative. ( positive * negative = negative)

8 0

3 years ago

Does this graph show a function? Explain how you know.

Lera25 [3.4K]

Answer: D) No. The graph fails the vertical line test.

Explanation:

We are able to draw a single vertical line that passes through more than one point on the red curve. For example, we could draw a vertical line through x = 5 and have it cross the red curve at (5,4) and (5,-4).

So this is one example where the graph fails the vertical line test. It passes this test when such a thing doesn't happen. In other words, a function is only possible if any x input leads to exactly one and only one y output.

In this case, x = 5 leads to multiple outputs y = 4 and y = -4 at the same time. There are other x values which this occurs as well (any x values such that x > 1). So this is why we don't have a function.

8 0

3 years ago