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3 years ago

I will give this much points for 7 (x+5)

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:7x+35

Step-by-step explanation:

amid [387]3 years ago

4 0

Answer:

7x+35

Step-by-step explanation:

7(x+5)

=(7)(x+5)

=(7)(x)+(7)(5)

=7x+35

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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

2 years ago

Which are perfect squares check all that apply 72 36 8 16 81 64 48

Julli [10]

Answer:36 16

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please Help, this is math problems

MariettaO [177]

Answer:

1/8 for the first one then 1/6 for the second one

Step-by-step explanation:

5 0

2 years ago

The ratio of 6:5 can be expressed as

Helen [10]

Answer:

the ratio of 6:5 can be expressed as 6/5

7 0

2 years ago

Bailey bought a lawnmower for $600. The value of the lawnmower depreciates 2% every year. What is the value of the lawnmower aft

givi [52]

Answer:

$542

Step-by-step explanation:

we know that

The equation of a exponential decay function is given by

$y=a(1-r)^x$

where

y is the value of the lawnmower

x is the time in years

a is the initial value

r is the rate of change

we have

$a=\$600\\r=2\%=2/100=0.02$

substitute

$y=600(1-0.02)^x$

$y=600(0.98)^x$

For x=5 years

$y=600(0.98)^5=\$542$

8 0

2 years ago