4 colour needed for this…i think
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Answer:
- Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
- Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E
Step-by-step explanation:
The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.
The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.
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<em>Additional comment</em>
The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.
The equation for a quadratic is as follows:
y = ax^2+bx+c
The first variable “a” determines whether the parabola opens up or down
The squared allows the equation to look like the parabola swoop when graphed.
The c term is the constant term
Answer: To find the volume of a cube, use the formula V=lwh, or Volume equals length times width times height.
1/3 + 1/6
---Find a common denominator, or the least common multiple of the given denominators. In this case, that would be 6.
1/3 = 2/6
1/6 = 1/6
---Now add the fractions
2/6 + 1/6
3/6
---Simplify/Reduce the fraction
3/6
1/2
Answer: 1/2
1/3 + 1/6 = 2/6 + 1/6 = 3/6 (or 1/2)
Hope this helps!
