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Kruka [31]
2 years ago
14

Writing unit fractions to add or subtract.

Mathematics
2 answers:
KonstantinChe [14]2 years ago
6 0

Answer:

the 2/3 will become 2/6

answer =  1/2

Step-by-step explanation:

2/6+1/6=3/6 redices to 1/2

Ivahew [28]2 years ago
3 0

1/3 + 1/6

---Find a common denominator, or the least common multiple of the given denominators. In this case, that would be 6.

1/3 = 2/6

1/6 = 1/6

---Now add the fractions

2/6 + 1/6

3/6

---Simplify/Reduce the fraction

3/6

1/2

Answer: 1/2

1/3 + 1/6 = 2/6 + 1/6 = 3/6 (or 1/2)

Hope this helps!

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Consider the function on the interval (0, 2π). f(x) = sin x + cos x (a) Find the open intervals on which the function is increas
Annette [7]

Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)

Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as \sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} }  ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\

Using these result in equation a we get

f(x) = \sqrt{2} [ cos(45)sin(x)+sin(45)cos(x)]\\\\= \sqrt{2} [sin(45+x)]..........(b)

Now we know that for derivative with respect to dependent variable is positive for an increasing function

Differentiating b on both sides with respect to x we get

f '(x) = f '(x)=\sqrt{2}  \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0

where x∈(0,2π)

we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

Thus for cos(π/4+x)>0 we should have

1) π/4 + x < π/2  => x<π/4  => x∈[0,π/4]

2) π/4 + x > 3π/2  => x > 5π/4  => x∈[5π/4,2π]

from conditions 1 and 2 we have  x∈(0,π/4)∪(5π/4,2π)

Thus the function is decreasing in x∈(π/4,5π/4)

5 0
3 years ago
Solve for n.<br> 17.1 = 5.7 x n
cluponka [151]

Answer:

n = 3

Step-by-step explanation:

<u>Equation:  17.1 = 5.7 * n</u>

<em>Divide both sides by 5.7 to get n by itself.</em>

<u>Step 1:  Divide both sides by 5.7</u>

17.1 = 5.7 * n

17.1 <u>/ 5.7</u> = 5.7 * n <u>/ 5.7</u>

    divide            divide

<em>3 = n</em>

Answer:  n = 3

7 0
4 years ago
Read 2 more answers
How much money, invested at an interest rate of r % per year compounded continuously, will amount to A dollars after t years? (R
Talja [164]
A=A(1+r/100)^t
a=17000(1+.043)^3
a=19.288.65
a is your money after 3 years
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3 years ago
The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than
jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

-13x + 2 = -28 - - - - - - - - -5

subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

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6 0
3 years ago
Find all numbers between 200 and 500 which have exactly 9 factors
MakcuM [25]

Answer:

225, 256, 441, 484

Step-by-step explanation:

Only square numbers can have an odd number of factors, e.g. 4: 1, 2, 4

Therefore only square numbers can have 9 factors.

There are only 8 square numbers between 200 and 500: 225, 256, 289, 324, 361, 400, 441, 484.

One way is to list all the factors of each number and you will find that only 225, 256, 441 and 484 have 9 factors.

The other more efficient way is to acknowledge the fact that if a square number (n x n) has 9 factors, n must have only 4 factors. For example, 225 has 9 factors because it is equal to 15 squared and 15 only has 4 factors: 1, 3, 5, 15.

This way, we can find out that 15, 21 and 22 have exactly 9 factors. However, 256 has 9 factors as well as it is equivalent to 2 to the power of 8. This means that it already has 8 factors: 2, 4, 8, 16...,128, 156. However, we must include 1 as a factor which means it has 9 factors in total as well.

3 0
3 years ago
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