Stokes' theorem equates the line integral of along the curve to the surface integral of the curl of over any surface with the given curve as its boundary. The simplest such surface is the triangle with vertices (1,0,1), (0,1,0), and (0,0,1).
Parameterize this triangle (call it ) by
with and . Take the normal vector to to be
Divide this vector by its norm to get the unit normal vector. Note that this assumes a "positive" orientation, so that the boundary of is traversed in the counterclockwise direction when viewed from above.
Compute the curl of :
Then by Stokes' theorem,
where
The integral thus reduces to
Answer:
Option b.
Step-by-step explanation:
Sample size n = 9
sample mean = 217.222
Standard deviation s = 1.202
alpha a = 0.025
H0 : u = 216
H1 : u > 216 ( claim)
Now run a T test and result is :
Test statistic, t =
t =
=
t = 3.0509
Critical value = t(a,n-1) = t(0.025,9-1)
= 2.306
Since t > critical value, Hence reject H0.
Option b. is the answer. Yes, because computed t is greater than the critical value.
265 x 0.06 = 15.9
265 - 15.9 = 249.1
249.1 is your answer
hope this helps
The angles that share the same tangent value as of tan 45 degrees would be in Quadrant III. This is because in this quadrant the ratios would equal a positive value, which is the same as in the first quadrant, also positive. Tan 45 = 1.
We would need both the x and the y values be either both positive or negative to get a positive final value.
120≈100
230≈200
455≈500
175≈200
(100+200+500+200)÷4=250
Hope my answer helped u :)