This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
We are given with two current costs : $3,450 for tables and $3,950 for chairs .The total cost then is equal to $7,400. This is said to be 4% more than he spent last year. so last year's expenses should be <span> $7,400 / 1.04 equal to $7115.39. The cost last year is expected to be less</span>
3/4=12/16
12/16 is greater than 11/16
Answer: 2
Step-by-step explanation:
try each value in the equation
2(0) + 1 = 3
0 + 1 = 3
1 ≠ 3
so 0 doesn’t work
2(1) + 1 = 3
2 + 1 = 3
3 = 3
this works, so the answer is 1
