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3 years ago

Help me on this we have to choose all the possible ones for that angle

Mathematics

1 answer:

viva [34]3 years ago

7 0

Answer:

Adjacent and complementary angle

hope it helps and your day will be full of happiness

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Need help on this as soon as possibke

miss Akunina [59]

LA = perimeter of base x height

Use Pythagorean theorem to find the base

4^2 + 6^2 = 52
Sq root of 52 is 7.2111...

4+6+7.2 = 17.2

17.2 x 8

137.6 is your answer

3 0

3 years ago

Need to find volume, step by step explanation pls

worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

$V_1=\dfrac{2}{3}\pi r^3$

Where, r is the radius of the hemisphere.

$V_1=\dfrac{2}{3}(3.14)(6)^3$

$V_1=\dfrac{6.28}{3}(216)$

$V_1=452.16$

Volume of cylinder is:

$V_2=\pi r^2h$

Where, r is the radius of the cylinder and h is the height of the cylinder.

$V_2=(3.14)(6)^2(12)$

$V_2=(3.14)(36)(12)$

$V_2=1356.48$

We know that,

$l^2=r^2+h^2$ [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

$(10)^2=(6)^2+h^2$

$100-36=h^2$

$\sqrt{64}=h$

$8=h$

Volume of cone is:

$V_3=\dfrac{1}{3}\pi r^2h$

Where, r is the radius of the cone and h is the height of the cone.

$V_3=\dfrac{1}{3}(3.14)(6)^2(8)$

$V_3=\dfrac{25.12}{3}(36)$

$V_3=301.44$

Now, the volume of the combined figure is:

$V=V_1+V_2+V_3$

$V=452.16+1356.48+301.44$

$V=2110.08$

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0

3 years ago

What is the value of x in the circle below? If necessary round your answer to the nearest tenth. I AM FAILING THIS CLASS I JUST

emmainna [20.7K]

Since we know that the 38 is being bisected (which we can tell by the fact that the line hits it perpendicularly), we know that from the intersection to the edge of the circle is 19. From this we can create a right triangle in which the legs are 10 and 19 and the hypotenuse is a radius of the circle. Since x is also a radius of the circle, all we have to do is use that information to find the hypotenuse using the Pythagorean Theorem and we have x.

Pythagorean Theorem
$a^{2}$ + $b^{2}$ = $c^{2}$
$10^{2}$ + $19^{2}$ = $x^{2}$
100 + 361 = $x^{2}$
461 = $x^{2}$
x = $\sqrt{461}$ or about 21.47