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3 years ago

Suppose you want purchase a new bicycle without using credit. The cost of the bike

Mathematics

2 answers:

9966 [12]3 years ago

8 0

About 5.5 months. please mark me brainliest. have a great day and good luck with school

Crank3 years ago

4 0

Answer:

5 and 1/2 months

Step-by-step explanation:

because because if you waited six months then you would go over and you would be paying $450

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4h = 17 <br> what is the letter H?

Dafna1 [17]

Answer:

4.25

Step-by-step explanation:

6 0

3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

4 years ago

Read 2 more answers

Need help asap pls and ty.

Anastasy [175]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be

rusak2 [61]

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$ .

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that $v = 3*10^{8}$ m/s.

We have to find d. So:

$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

7 0

3 years ago

The slopes of perpendicular line segments are 1/2 and d/3 What is the value of d?

pychu [463]

Perpendicular slopes have a product of -1, thus $\bf \cfrac{1}{2}\cdot \cfrac{d}{3}=-1$

solve for "d"

4 0

3 years ago

Read 2 more answers