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Rainbow [258]
3 years ago
5

How would you explain the proper use of distributive property ? ​

Mathematics
1 answer:
Maksim231197 [3]3 years ago
3 0
Start with the word “distribute” meaning to pass equally. Now distributive property means to distribute equally. For example 2(4x+5) you wanna distribute the 2 amount the parentheses so that it’s”distributed evenly. 2(4x+5) is now 8x+10
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Crystal randomly selects a card from the list and
MariettaO [177]
Sorry, don’t know the answer
3 0
3 years ago
Please help me, Love you
Anton [14]

Answer:

It would be 750

Step-by-step explanation: You have to divide it by 5 and then times it by 3.

8 0
2 years ago
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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
What is the slope of the line passing through the points (4,3) and (1,-2​
Feliz [49]

Answer:

8/5

Step-by-step explanation:

7 0
3 years ago
If f(x)=x sqrt -25 and g(x)=x-5, what is the domain of (f/g)(x)?
givi [52]

Answer:

<h2>R-{5}</h2>

Step-by-step explanation:

f(x)=x²-25=(x-5)(x+5)

g(x)=x-5

(f/g)(x)=<em>(x-5)</em>(x+5)/<em>(x-5)</em>=x+5;   for x≠5

D=R-{5}

4 0
3 years ago
Read 2 more answers
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