QUESTION 1
The given system of equations are:
We equate the two equations to get:
When x=0,
The solution is (0,1)
QUESTION 2
The given equations are:
and
We equate both equations to get:
Group similar terms,
We put x=0 into any of the equations to find y.
The solution is (0,-1).
QUESTION 3
The given equations are:
and
We equate both equations:
Group similar terms:
This is not true.
Hence the system has no solution.
70.24, That should be right
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8²+9(12÷3×2)-7
well we are going to start in the parentheses and do order of operations
so 12÷3=4
then 4×2=8
so you have 8² +9(8)-7
well we still need to get rid of the parentheses 9×8=72
so then we are left with 8²=72-7
so now we have to get rid of the exponents so8²=64
64+72-7
136-7=129
so 129 is your answer to the first one.
the second one is easy. its a single step equation.
you are trying to get x by itself. so you have 7x=42. you want to get rid of the seven so you have to do the opposite of what it is doing to x. the 7 is multiplying by the x. So whats the opposite of multiplication... division. so you have to divide both sides by 7. so you have 7÷7x=42÷7
now simplify and you have x=6
Ene score of the first test Is 56. Each test score is 2 points higher than the previous test score. So the score of the second test is 56+ 2 = 58.
The score of the third test is 58+ 2= 60.
And so on.
The scores form an arithmetic sequence 56, 58, 60, ......... with common difference 2.
But the values of the given exponential function \(s(n)=28*2^n\), describe a geometric sequence with common ratio 2.
So the exponential function cannot be used to model this problem.
