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3 years ago

I need help with this if you get it right I will mark you

Mathematics

1 answer:

Schach [20]3 years ago

3 0

Answer:

ok then

Step-by-step explanation:

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Martin charges $10 for every 5 bags of leaves he rakes. Last weekend, he rakes 24 bags of leaves. How much money did he earn?

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He will receive $48 dollars

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3 years ago

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Find the area of the trapozoid.

Bad White [126]

Area =

$\frac{1} {2} \times sum \: of \: parallel \: sides \: \times height$

=》

$\frac{1}{2} \times (6 + 10) \times 5$

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$\frac{1}{2} \times 16 \times 5$

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$8 \times 5$

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$40$

Area = 40 in²

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3 years ago

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PLZ HELP ITS DUE RIGHT NOW

german

I would say A because it would just make sense, i’m sorry!

7 0

3 years ago

Simplify the expression : l-8l + l8l

NikAS [45]

16 it will be a positive number because it's the opposite of |-8| but it was -|8| then it would be a neg number

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4 years ago

Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

$z=\sqrt{\dfrac{1371}{196}}\sin t$

(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

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4 years ago