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mrs_skeptik [129]
3 years ago
13

PLEASE HELP ! Will reward brainliest

Mathematics
2 answers:
faltersainse [42]3 years ago
3 0
Last two, because of stuff
(counts characters)
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babymother [125]3 years ago
3 0
Here you go. :)
This one is easy to determine through process of elimination. A pictograph uses pictures and symbols to display information, also known as data. A line graph uses nothing but lines and points. Thus, a pictograph is <em>not </em>another name for a line graph, and so the answers are 2 and 3. A pictograph, since it uses just pictures, is easy to distort and can be very misleading.
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baherus [9]

{4}^{5}   \div  {4}^{2}  \\  = {4}^{5 - 2}  \\  = 4^{3}

5 0
2 years ago
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Solve the equation on the interval [0,2pi] 5sec(x)+7=-3
vovangra [49]

Answer:

Hello,

x\in \bigg\{\dfrac{2\pi}{3} ,\dfrac{4\pi}{3}\bigg\}\\

Step-by-step explanation:

5*sec(x)+7=-3\\\\sec(x)=\dfrac{-10}{5} \\\\\dfrac{1}{cos(x)} =-2\\\\cos(x)=-\dfrac{1}{2} \\\\x=120^o\ or\ x=240^o\\

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3 years ago
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White raven [17]
55 because it's out 100
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3 years ago
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WILL GIVE BRAINLY PLEASE HELPPPPP
erica [24]

Answer:

C

Step-by-step explanation:

4(8-x)=8

32-4x=8

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x=6

5 0
3 years ago
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Can someone solve this with steps cause idk how to solve the radicals
IceJOKER [234]
\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}&#10;343=7\cdot 7\cdot 7\\&#10;\qquad 7^3\\&#10;36=6\cdot 6\\&#10;\qquad 6^2\\&#10;256=4\cdot 4\cdot 4\cdot 4\\&#10;\qquad 4^4&#10;\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}&#10;\\\\\\&#10;\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}&#10;\\\\\\&#10;7^2+6-4^3\implies 49+6-64\implies -9


to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.
8 0
3 years ago
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