30 points for anyone that can solve the question

Select all the expressions that are equivalent to the polynomial below.

katrin2010 [14]

The answers are: D and C and A and E
because:

B 3(x - 5) - 2(6x2 + 9x + 5)=−12x^2−15x−25

F (4x2 - 13x - 7) - (16x2 + 9x - 5)=−12x2−22x−2

E (-15x2 + 9x - 10) + (3x2 - 10x - 5)=−12x^2−x−15

4 0

3 years ago

Read 2 more answers

a taco stand sells tacos for $3.25 each. the stand's expenses for the day are $210. definec your variables and write an inequali

AlekseyPX

Okay, we know that the expenses for the day is 210.

Knowing this, and the price of the taco, we write the inequality:

3.25t > 210

t = number of tacos

Now divide both sides by 3.25:

t > 64.62 (rounded)

Because a taco stand can't sell a fraction of a taco, we know that the taco stand has to sell more than 65 tacos for a profit.

7 0

3 years ago

The table below shows one doctor's patients who got the flu and whether or not they took a vitamin each day. What is P(took a vi

In-s [12.5K]

Answer:

1/4

Step-by-step explanation:

25 people took a vitamin and still got the flu and the total number is 100 so the fraction is 25/100 which can be reduce to 1/4

7 0

3 years ago

17. A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find

Pavlova-9 [17]

Answer:

$r = 3.74cm$

Step-by-step explanation:

Given

Hemisphere

$Radius = 7cm$

Cone

$Height = 49m$

Required

Determine the radius of the cone

First, we calculate the volume (V1) of the hemisphere.

$V_1 = \frac{2}{3}\pi r^3$

Substitute 7 for r

$V_1 = \frac{2}{3}\pi * 7^3$

$V_1 = \frac{2}{3}\pi * 343$

$V_1 = \frac{686}{3}\pi$

Volume (V2) of a cone is:

$V_2 = \frac{1}{3}\pi r^2h$

Because the lead is cast into a cone, then they have the same volume.

So, we have:

$\frac{686}{3}\pi = \frac{1}{3}\pi r^2h$

$686 = r^2h$

Substitute 49 for h

$686 = r^2 * 49$

Divide both sides by 49

$r^2 = \frac{686}{49}$

$r^2 = 14$

$r = \sqrt{14$

$r = 3.74cm$

Hence, the radius of the cone is 3.74cm

5 0

3 years ago

A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3 4

dimaraw [331]

Given :

A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3/4 pounds the first month and 11 5/8 pounds the second month.

To Find :

How much weight must be lost the third month for the goal to be achieved.

Solution :

Let, weight lose in third month is x.

So, 8 3/4 + 11 5/8 + x = 26

$\dfrac{32+3}{4}+\dfrac{88+5}{8}+x=26\\\\x = 26 - ( \dfrac{35}{4}+\dfrac{93}{8})\\\\x=5.625\ pounds$

Therefore, weight lose in third month is 5.625 pounds.

Hence, this is the required solution.

3 0

3 years ago

30 points for anyone that can solve the question ​

30 points for anyone that can solve the question