3 years ago

30 points for anyone that can solve the question

Mathematics

1 answer:

marusya05 [52]3 years ago

5 0

The solution to this problem is 5/2a^2b^5

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What is the substitution of -6x-8y=-20 and x+6y=-6

ale4655 [162]

Substitution doesn't work for this, but elimination does.

-6x-8y=-20 +6( x+6y=-6)

-6x-8y=-20 + 6x+36y=-36

-6x and 6x cancel each other, add -8 and 36 to get 28, and -20 and -36 to get -56.

28y=-56

divide by 28 on both sides.

Y= -2

Then substitute y into one of the equations.

x+6(-2)=-6

x-12=-6

x=6

The ordered pair is (6,-2).

5 0

3 years ago

Read 2 more answers

In 2010 the Internal Revenue Service allowed a $5,150 deduction for each dependent. In 2005 it was a $3,200. If a family has fiv

Aleks04 [339]

5x5,150 =$<span>25,750 = Answer</span>

Deductions per dependent $5,150 times 5 in 2010

6 0

3 years ago

Please look at the image

Alina [70]

Answer:

F=2E

ANGLE F+ANGLE E=120

2E. + E. =120

3E=120

E=40

4 0

3 years ago

Learning goal: to understand the rules for computing dot products. let vectors a=(2,1,−4), b=(−3,0,1), and c=(−1,−1,2). part a -

miv72 [106K]

For this case we have the following vectors:
$a = (2,1, -4)

b = (- 3,0,1)

c = (- 1, -1,2)$
The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
$a.b = (2,1, -4). (- 3,0,1)

a.b = (2) (- 3) + (1) (0) + (-4) (1)

a.b = - 6 + 0 - 4

a.b = - 10$
Answer:
The product point of the vectors a and b is:
$a.b = - 10$

3 0

3 years ago

One of the legs of a right triangle measures 7 cm and its hypotenuse measures 12 cm.

Oksana_A [137]

Answer:

AC ≈ 9,7sm

Step-by-step explanation:

AB=7 One side of a right triangle

BC=12 Hypotenuse of a right triangle

AC=?=x The other side of a right triangle

x²+7²=12²

x²=144-49

x²=95

x=√(95) ≈ 9,7

AC ≈ 9,7sm

3 0

2 years ago

30 points for anyone that can solve the question ​

30 points for anyone that can solve the question