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boyakko [2]
2 years ago
12

Explica como procederias para obter cristais de sulfato de potássio a partir de ácido sulfúrico e hidróxido de potássio. Escreve

a respetiva equação de palavras e equação química.
Chemistry
1 answer:
iren2701 [21]2 years ago
3 0
Translate it to English and I would love to help u out (:
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how many H+ ions are in a solution with a pH of 2 and how many H+ ions are in a solution with a pH of 6?
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Answer:

i) pH = 2

pH = -log(H+)

:- (H+) = 10^(-2)

:- (H+) = 0.01 M

ii) pH = 6

pH = -log(H+)

:- (H+) = 10^(-6)

:- (H+) = 0.000001 M

Explanation:

By definition: pH = -log(H+).

Given your pH, solve for the H+ using the the following log rule:

if a = (+/-) log (b) then

b = 10^((+/-) a).

Also remember unit of concentration is molar (M)

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In a chemical equation, what do the coefficients indicate?
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In a chemical equation coefficients indicate the number of molecules/atoms involved in the reaction.
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Periodic table 50 elements with thier valancies​
Lubov Fominskaja [6]

Answer:

The first 50 elements along with their valences are given below :

1. Hydrogen = 1

2. Helium = 0

3. Lithium = 1

4. Beryllium = 2

5. Boron = 3

6. Carbon = 4

7. Nitrogen = 3

8. Oxygen = 2

9. Fluorine = 1

10. Neon = 0

11. Sodium = 1

12. Magnesium = 2

13. Aluminium = 3

14. Silicon = 4

15. Phosphorus = 3

16. Sulphur = 2

17. Chlorine = 1

18. Argon = 0

19. Potassium = 1

20. Calcium = 2

21. Scandiun = 3

22. Titanium = 3

23. Vanadium = 4

24. Chromium = 3

25. Manganese = 4

26. Iron = 2

27. Cobalt = 2

28. Nickel = 2

29. Copper = 2

30. Zinc = 2

31. Gallium = 3

32. Germanium = 4

33. Arsenic = 3

34. Selenium = 2

35. Bromine = 1

36. Krypton = 0

37. Rubidium = 1

38. Strontium = 2

39. Yttrium = 3

40. Zirconium = 4

41. Niobium = 3

42. Molybdenum = 3

43. Technetium = 7

44. Ruthenium = 4

45. Rhodium = 3

46. Palladium = 4

47. Sliver = 1

48. Cadmium = 2

49. Indium = 3

50. Tin = 4

<u>Note</u> :

An element like Iron, copper can have more than one valencies.

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When the equation N=O/P is solved for P correctly, the equation should read:
zheka24 [161]

Given the equation N=O/P, solve for P by multiplying the left and right by P/N:

N * P/N = O/P * P/N

P = O/N


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