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Kay [80]
3 years ago
12

Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor: 4nh3 + 5o2 → 4no + 6h2o when 40.0 g nh3 and 50.0 g o2

are allowed to react, which is the limiting reagent?
Chemistry
1 answer:
Illusion [34]3 years ago
4 0

Convert the mass to moles:

40.0 grams of NH3 / 17.03 g/mol = 2.35 moles NH3<span>
<span>50.0 grams of O2 / 31.998 g/mol = 1.56 moles O2</span></span>

Get the actual ratio:

NH3/O2 = 2.35 / 1.56 = 1.5

 

The theoretical ratio is 4 NH3 to 5 O2, that is:

(NH3/O2)theo = 4 / 5 = 0.8

 

<span>Since actual > theoretical and the ratio is NH3/O2, therefore the limiting reagent is O2.</span>
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