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3 years ago

Calculate the MADs for the teachers' scores. Did the teachers make progress in standardizing the scores?

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

The teacher made progress in standardizing the test scores from the beginning of the year to the end. The MAD tells us this because the difference in the teachers scores from the mean is less at the end. The Mean Absolute Deviation is a measure of variability, and the smaller the number, the less variability there is in the answers. So, in this example there are more scores closer to the average than when they first graded the essays.

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2 years ago

Find the y intercepts of 3x^2+24x-51. quadratic formula

julia-pushkina [17]

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Firstly, starting with the y-intercept. To find the y-intercept, set the x variable to zero and solve as such:

$y=3*0^2+24*0-51\\y=0+0-51\\y=-51$

Your y-intercept is (0,-51).

Next, using our equation plug the appropriate values into the quadratic formula:

$x=\frac{-24\pm \sqrt{24^2-4*3*(-54)}}{2*3}$

Next, solve the multiplications and exponent:

$x=\frac{-24\pm \sqrt{576-(-648)}}{6}\\\\x=\frac{-24\pm \sqrt{576+648}}{6}$

Next, solve the addition:

$x=\frac{-24\pm \sqrt{1224}}{6}$

Now, simplify the radical using the product rule of radicals as such:

Product Rule of Radicals: √ab = √a × √b

√1224 = √12 × √102 = √2 × √6 × √6 × √17 = 6 × √2 × √17 = 6√34

$x=\frac{-24\pm 6\sqrt{34}}{6}$

Next, divide:

$x=-4\pm \sqrt{34}$

The exact values of your x-intercepts are (-4 + √34, 0) and (-4 - √34, 0).

Now to find the approximate values, solve this twice: once with the + symbol and once with the - symbol:

$x=-4+ \sqrt{34},-4- \sqrt{34}\\x\approx 1.83, -9.83$

The approximate values of your x-intercepts (rounded to the hundredths) are (1.83,0) and (-9.83,0).

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3 years ago

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Harlamova29_29 [7]

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3 years ago

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3 years ago

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djverab [1.8K]

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3 years ago

Read 2 more answers