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Ira Lisetskai [31]
2 years ago
6

HELP I NEED HELP ASAP

Mathematics
2 answers:
liubo4ka [24]2 years ago
6 0
I believe the answer is C
Elis [28]2 years ago
4 0
The answer i think is it c
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What are the solutions to the quadratic equation 4x^2-9x-9=0?
gavmur [86]
X = 3, -
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(4m+3)9+6m how do i solve it?
alexandr402 [8]
36m+27+6m=0### 30m=27###m=9/10
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(PART A PART B) PLEASE HELP!!! DUE TODAY!!!! ❤️
maxonik [38]

Answer:

the anser from what i see should be option 1

Step-by-step explanation:

The reason why i say this is because number 1 is linear which means it is just multipying but your multiplying and adding and its not option 3 because question 5 said the questions started at 1

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%
andrey2020 [161]

First observe that if a+b>0,

(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}

Let a=0 and b=x. It follows that

a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}

Now let b=1, so a^2+a=4x. Solving for a,

a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2

which means

a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}

Now solve for x.

x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2

(note that we assume 2x-1\ge0)

4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}

(we omit x=0 since 2\cdot0-1=-1\ge0 is not true)

3 0
1 year ago
Determine the measure of angle BZC.
dusya [7]

Answer:

70 degrees

Step-by-step explanation:

Angle BZA = Angle BZC = 20 degrees

Reason : These two angles are Vertically opposite angles.

Angle BZA + Angle BZC = 90

20 + Angle BZC = 90

Angle BZC = 90 - 20

Angle BZC = 70 degrees

8 0
3 years ago
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