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Kipish [7]
3 years ago
13

Identify the % of change as an increase or decrease.

Mathematics
1 answer:
Verizon [17]3 years ago
4 0
It is a percent increase and it increased by 15%

I got this answer by doing 24.61/21.40 which equals 1.15

You can check this answer by doing 21.40 * .15 on a calculator and when you do this you get 3.21 which you can then add back to 21.40 to get $24.61
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Carly and rob combined their dvd collection now they have 42 dvds all together. Carly had 4 more dvds than rob how many dvds did
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If Carly had more DVDs than Rob then you would subtract her amount away from the total. 42-4=38
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3 years ago
Divide the given polynomial by the given monomial.​
yanalaym [24]

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6 0
2 years ago
The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.
Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

<em>Let X = number of hours spent per week on household chores</em>

So, assuming data follows normal distribution; X ~ N(\mu=28,\sigma^{2}=7^{2})

The z score probability distribution for sample mean is given by;

               Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean hours = 28

            \sigma = standard deviation = 7 hours

            n = sample of adults = 49

<em>Let </em>\bar X<em> = sample mean hours spent per week on household chores</em>

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P(\bar X > 26.75 hours)

    P(\bar X > 26.75 hours) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{26.75-28}{\frac{7}{\sqrt{49} } } ) = P(Z > -1.25) = P(Z < 1.25)

                                                                     = 0.89435  {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

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3 years ago
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B.
you move the decimal point to the left once
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