Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
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Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0} and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
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60 times
You have a 1/3 chance each spin.
1/3 = x/180
180 = 3x
x = 60
Answer:
688 cm²
Explanation:
Area of triangular prism = Base × Height + Length × (perimeter of base)
Here given:
- Perimeter of Base: (6 + 12.4 + 12.4) = 30.8 cm
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Surface Area = 6 × 12 + 20 × (30.8) = 688 cm²
Answer:
A = π(P)
I can't give a numeral answer because neither P nor A is defined.