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Svetradugi [14.3K]
3 years ago
12

Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0
An=a1+d(n-1)
a1=first term
d=common difference
n=which term

common difference is 5 first term is 2
an=5+2(n-1)
19th term is n=19
a19=5+2(19-1)
a19=5+2(18)
a19=5+36
a19=41

19th term is 41
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The length of the given rectangle is 10 units.

Here, we are given that the perimeter of a rectangle is 36 units.

A rectangle is a figure with 4 sides and opposite sides equal. The perimeter of a rectangle is calculated using the given formula-

Perimeter = 2 ( length + breadth )

Here, the breadth (width) is given to be 8 units.

Let the length be x units.

Then, we can form the following equation-

Perimeter = 2( x + 8 )

36 = 2x + 16

36 - 16 = 2x

20 = 2x

2x = 20

x = 20/2

x = 10

Thus, the length of the given rectangle is 10 units.

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1 year ago
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Answer:

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Answer:

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