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3 years ago

Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.

1 answer:

4 0

An=a1+d(n-1)
a1=first term
d=common difference
n=which term

common difference is 5 first term is 2
an=5+2(n-1)
19th term is n=19
a19=5+2(19-1)
a19=5+2(18)
a19=5+36
a19=41

19th term is 41

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