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Svetradugi [14.3K]
4 years ago
12

Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.

Mathematics
1 answer:
emmasim [6.3K]4 years ago
4 0
An=a1+d(n-1)
a1=first term
d=common difference
n=which term

common difference is 5 first term is 2
an=5+2(n-1)
19th term is n=19
a19=5+2(19-1)
a19=5+2(18)
a19=5+36
a19=41

19th term is 41
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Answer:

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Step-by-step explanation:

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Otherwise, we can say that it forms all different. The dilation factor which translates that bottom left point of shape I to form II is 2. But this does not map the other shape I vertices onto form II. There's, therefore, no dilation in form I of maps on form II.

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3 years ago
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Amiraneli [1.4K]

Answer:

t = 13

Step-by-step explanation:

3 months ------ 4500

6 months ------ x

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cross multiplation:

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Answer:

3/11

Step-by-step explanation:

given that a cell phone company has three different production sites

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Production                  60%                         30%                10%             100%

Recalled                        5%                           7%                   9%                  

Prob for recall            0.003                       0.021             0.009         0.033

Total probability for recall = 0.033

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So required probability

= If a randomly selected cell phone has been recalled, what is the probability that it came from Site 3

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