Find the 19th term of the arithmetic sequence whose common difference is =d5 and whose first term is =a12.
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Answer:
Please check the explanation.
Step-by-step explanation:
Given the sequence
2, 6, 10, 14, 18
An arithmetic sequence has a constant difference and is defined as
compute the differences of all the adjacent terms
The difference between all the adjacent terms is the same.
Thus,
and
Therefore, the nth term is computed by:
Thus, position to term rule of 2, 6, 10, 14, 18 multiply by __4___ and subtract by __2__.