All categories

3 years ago

Pls help and explain

Mathematics

1 answer:

grin007 [14]3 years ago

4 0

Answer:

Step-by-step explanation:

First distribute the 2x to get:

4x² + 10x

Then distribute the -5 to get:

-10x - 25

Then combine

4x² + 10x - 10x - 25

The 10x's will cancel leaving you:

4x² - 25

You might be interested in

Explain how to determine if you have a direct variation or proportional relationship

neonofarm [45]

Answer:

straight line that passes through the origin

Step-by-step explanation:

Two variables are said to have a direct variation or proportional relationship if it can be represented by y = kx, where k is a constant.

Comparing this with the equation of a straight line y = mx + b, where m is the slope of the line and b is the y intercept (value of y when x = 0), We can tell if the say that the graph of a direct variation or proportional relationship is a straight line with no y intercept (b = 0, that is it passes through the origin).

8 0

3 years ago

Which number is prime? 49 51 53 55

Kryger [21]

Answer: 53

Step-by-step explanation: It is the only prime

6 0

3 years ago

Read 2 more answers

Drag step's into the order to correctly solve the equation 4×=112

goldfiish [28.3K]

X = 28
you divide 112 by 4 to get 28

5 0

3 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately 2020.022

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$