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malfutka [58]
3 years ago
5

Could you please solve this?

Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0

Answer:

x = 12

Step-by-step explanation:

The ray from the vertex to the base is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is

\frac{x}{9} = \frac{4}{3} ( cross- multiply )

3x = 36 ( divide both sides by 3 )

x = 12

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The box plot was created by using which pieces of data?<br> 1<br> 50<br> 75<br> 100<br> 125
VikaD [51]

Answer:

50,75,and 100 there's supposed to be a 20 too but it's not there but oh well

4 0
2 years ago
HELP PLEASE!!!!!!!!
MaRussiya [10]

The answer is C! I hope this helps

3 0
2 years ago
Read 2 more answers
This is important please help
Leya [2.2K]

Answer: C

<u>Step-by-step explanation:</u>

∑ 8(\frac{7}{3})⁽ⁿ⁻¹⁾ from n = 1 to n = 5

n = 1 → 8(\frac{7}{3})⁽¹⁻¹⁾

        = 8                                         = \frac{648}{81}

n = 2 → 8(\frac{7}{3})⁽²⁻¹⁾

         = \frac{56}{3}                                         = \frac{1512}{81}    

n = 3 → 8(\frac{7}{3})⁽³⁻¹⁾

          = \frac{392}{9}                                     = \frac{3528}{81}

n = 4 → 8(\frac{7}{3})⁽⁴⁻¹⁾

          = \frac{2744}{27}                                 = \frac{8232}{81}

n = 5 → 8(\frac{7}{3})⁽⁵⁻¹⁾

          = \frac{19208}{81}                                = \frac{19208}{81}

                                                                            Sum = \frac{33128}{81}

                                                                                    = 408.99

     

6 0
2 years ago
Given: ∆ABC –iso. ∆, m∠BAC = 120°
lidiya [134]

Answer: P\triangle ADH = (a+b+\sqrt{a^2+b^2} ) unit

Step-by-step explanation:

Since Here Δ ABC is a isosceles triangle.

Also, AH\perp BC and HD\perp AC

Thus, ∠ ADH = 90°

That is, Δ ADH is the right angle triangle.

In which, AD = a unit and HD = b unit

And, By the definition of Pythagoras theorem,

AH^2 = HD^2 + AD^2

⇒ AH^2 = a^2 +b^2

⇒ AH = \sqrt{a^2+b^2}

Since, the perimeter of a triangle = sum of the all sides of the triangle.

Therefore, perimeter of ΔADH = AD + DH + AH

= a + b + \sqrt{a^2+b^2} unit

4 0
3 years ago
For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel
adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

E=|\frac{p}{q}\cdot \frac{dq}{dp}  |

  • If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
  • If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
  • If E = 1, we say demand is unitary.

We have the following demand equation D(p)=-\frac{3}{4}p+29; p = 9

Applying the above definition of elasticity of demand we get:

E(p)=\frac{p}{q}\cdot \frac{dq}{dp}

where

  • p = 9
  • q = -\frac{3}{4}p+29
  • \frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)

\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}

Substituting the values

E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337

|E(9)|=|\frac{27}{89}| < 1

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0
3 years ago
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