Something to raise the moist air to form the clouds and cause precipitation. An example of lift is warm air colliding with cold air and being forced to rise over the cold dome. The boundary between the warm and cold air masses is called a front.

Step-by-step explanation:

6 0

3 years ago

A bag contains purple marbles and blue marbles, 41 in total. The number of purple marbles is 4 less than 2 times the number of b

Andreas93 [3]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

1) We have purple (p) and blue (b) marbles in a bag, and 41 marbles total so:

p+b = 41

2) we want to know how many purple marbles we have, so let's rearrange for p:

p = 41 - b

3) Our problem gives us an expression for the purple marbles in terms of the blue, let's write it using math symbols instead of words:

"The number of purple marbles is 4 less than 2 times the number of blue marbles."

so: p = 2b - 4

3) Now we're going to plug this in (or substitute it) for our p in our first equation, and solve for b

p = 41 - b

2b - 4 = 41 - b (substitution)

2b = 45 - b ( add 4 to both sides)

3b = 45 (add b to both sides)

b = 15 (divide both sides by 3)

4, last step!)

Now we know we have 15 blue marbles, that's great! But we still want to know how many purple marbles we have.

41- 15 = 26 purple marbles

4 0

3 years ago

Joaquin is constructing the perpendicular bisector of ab. What should be his first step?

natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of $\over{AB}$ .

Step-by-step explanation:

To construct a perpendicular for $\over{AB}$ , we must first take a compass & take the distance of its arms wider than half the length of $\over{AB}$ .

This is done in order to get two intersecting arcs in the top & bottom of $\over{AB}$ so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above $\over{AB}$ , draw a line joining these 2 points through their points of intersection. The point where it intersects $\over{AB}$ is the middle-most point of $\over{AB}$ & now a perpendicular bisector of $\over{AB}$ is constructed.

$\rule{150pt}{2pt}$

3 0

2 years ago

the cost of 5 cans of dog food is $4.35. at this price how much do 11 cans of dog food cost explain your reasoning. ASAP

mestny [16]

Answer:

Cost of 11 cans of Dog food is $9.57

Step-by-step explanation:

Cost of 5 cans of dog food = $4.35

So to find out the cost of 11 cans of dog food at the same price, we need to calculate the price of 1 can of dog food.

Calculation for finding out cost of 1 can of dog food

The price $4.35 which is given is the price of 5 cans

So to find the cost of 1 can, we need to divide the given price by 5

5 Cans of dog food = $4.35

1 can of dog food = 4.35 ÷ 5

1 can of dog food = $0.87

Now to find out the price of 11 cans, we will multiply the price of 1 can with 11

Cost of 11 cans = 11 × $0.87

= $9.57

6 0

3 years ago