Ask question

Ask question

All categories

Oksi-84 [34.3K]

3 years ago

10

Who can do my my 9th grade khan academy i’ll literally venmo you $10 (text me if you can)

1 answer:

Gennadij [26K]3 years ago

7 0

Answer:

i can oh and gys please follow me there is more to me thwn meets the eye

You might be interested in

Help in 5-14 plz I need this in the worst way

Maru [420]

Answer:

Rational

Step-by-step explanationRational interger:

7 0

2 years ago

Find the area between the curves x=-2,x=3,y=4x,y=x-5

mixas84 [53]

Those are all lines...

So the x interval is from -2 to 3, because of x=-2 and x=3

The upper line is y(u)=4x and the lower line is y(l)=x-5

So the area between the two lines is:

A=⌠y(u)-y(l) dx

A=⌠4x-x+5 dx

A=⌠3x+5 dx

A=[3x^2/2+5x]

A=[(3x^2+10x)/2], x=[-2,3]

A=(1/2)(27+30-(12-20))

A=(1/2)(57+8)

A=(1/2)(65)

A=32.5 u^2

5 0

3 years ago

An electronics company has been producing 1705 CD Players a day working two shifts. The second shift has produced 95 CD players

BartSMP [9]

First, make an equation.
y=4/5x-95
The first shift makes 1000 CD players, while the second shift makes 705 CD players.

6 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

In February, Alec had 1,562 visitors to his website. In March, he had 1,310 visitors to his website. What is the percentage decr

tigry1 [53]

Answer:

16.1% is the percentage decrease.

Step-by-step explanation:

We are given the following in the question:

Visitors in February = 1,562

Visitors in march = 1,310

We have to find the percentage decrease of the number of visitors to Alec's website from February to March.

Percentage decrease =

$=\dfrac{\text{Change}}{\text{Original}}\times 100\%\\\\=\dfrac{1562-1310}{1562}\times 100\%\\\\=\dfrac{252}{1562}\times 100\% = 16.1\%$

Thus, 16.1% is the percentage decrease in the number of visitors to Alec's website from February to March.

6 0

3 years ago