Answer:

Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\144^\frac{3}{2}=144^{1\frac{1}{2}}=144^{1+\frac{1}{2}}\qquad\text{use}\ a^na^m=a^{n+m}\\\\=144^1\cdot144^{\frac{1}{2}}=144\sqrt{144}=144\cdot12=1728](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C144%5E%5Cfrac%7B3%7D%7B2%7D%3D144%5E%7B1%5Cfrac%7B1%7D%7B2%7D%7D%3D144%5E%7B1%2B%5Cfrac%7B1%7D%7B2%7D%7D%5Cqquad%5Ctext%7Buse%7D%5C%20a%5Ena%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D144%5E1%5Ccdot144%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D144%5Csqrt%7B144%7D%3D144%5Ccdot12%3D1728)
Answer:
3.6 gB
Step-by-step explanation:
You can think of this question in terms of the y = mx+b equation.
$78.90 is y because it is the total amount per month, $4 is m because it is the cost per gB, and $64.50 is b because it is the flat rate.
78.9 = 4x + 64.5
4x = 14.4
x = 3.6 gB of data (or 3 if it wants a whole number)
Answer:
Grades 6 and 8
Step-by-step explanation:
If the relationship of girls to boys in two different grades are proportional, <u>they must have the same ratio</u>. To tackle this problem, we can find the <u>ratios</u> of genders in each grade and compare them.
Step 1, finding ratios:
Finding ratios is just like <u>simplifying fractions</u>. We will reduce the numbers by their<u> greatest common factors</u>.




<u>Can't be simplified!</u>
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Step 2:
Notice how grades 6 and 8 both had a ratio of 3:4. We can conclude that these two grades have a proportional relationship between girls and boys.
<em>I hope this helps! Let me know if you have any questions :)</em>
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Answer: The range is 13. The mean is 10. The standard deviation is 4.62 .
Step-by-step explanation:
The given data : 3, 6, 9, 11, 15, 16
Total number of data values : n = 6
The mean of data is given by :-

The standard deviation is given by :-

The range of the data : Maximum value -Minimum value

Answer:
3
Step-by-step explanation: