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3 years ago

A JanSport backpack that was recently on sale for $60 has been marked up 15%. What is the new retail price of that backpack?

1 answer:

6 0

The answer is $90.00

The reason is because you multiply 60 Times .15 and you get .900 then, you move your decimal over twice and get $90.00

Hope this helps you out!

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Jane takes her cat to the veterinarian. The veterinarian charges a $45 initial charge for the visit plus $22.50 per vaccine. Whi

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The answer is D

Explanation:22.5 is how much each vaccine is and x is how many vaccines while y is the total cost and 45 is a standard fee

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3 years ago

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6. The basketball team scored points by

Nikolay [14]

Answer:

36, 2×2×3×3

Step-by-step explanation:

8 free throws= 8×1=8

14 2 point baskets= 14×2=28

8+28=36

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3 years ago

Answer quick for brainliest

umka2103 [35]

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Step-by-step explanation:

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3 years ago

NEED HELP !! There are 16 ounces in 1 pound . How many 12-ounce servings are in 36 pounds of dog food ? PLEASSSEEDE

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There are (3) 12 ounce servings of dog food

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3 years ago

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If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, of the box with a square base are described below:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - Side length of the base, in centimeters.

$h$ - Height of the box, in centimeters.

By (2), we clear $h$ within the formula:

$h = \frac{V}{l^{2}}$

And we apply in (1) and simplify the resulting expression:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Then, we find the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find the critical value of the side length of the base is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Then, we evaluate this result in the expression of the second derivative:

$V'' = -600$

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The largest possible volume of the box is 2000000 cubic meters.

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3 years ago