Your answer will be 21,550 because of 12,000*1.7958563=21,550
Answer:
Completing the square answer

Solution set
= 
Step-by-step explanation:
Assuming the question is correctly interpreted as 2m2 = 2m², here is how to proceed
We have 
Divide by 2 on both sides

Take half of the coefficient of
and square it
![\left[ - \frac{3}{2} \cdot \frac{1}{2} \right]^2 = \frac{9}{16}](https://tex.z-dn.net/?f=%5Cleft%5B%20%20-%20%5Cfrac%7B3%7D%7B2%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%5D%5E2%20%3D%20%5Cfrac%7B9%7D%7B16%7D)
Add the result to both sides

can be re-written as a perfect square

The RHS becomes

Therefore,

Take the square root of both side
![m - \frac{3}{4} = \pm \sqrt[]{ - \frac{391}{16}}](https://tex.z-dn.net/?f=m%20%20-%20%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cpm%20%5Csqrt%5B%5D%7B%20-%20%5Cfrac%7B391%7D%7B16%7D%7D)
Simplify
![m - \frac{3}{4} = \pm \frac{\sqrt[]{391}i}{4}](https://tex.z-dn.net/?f=m%20%20-%20%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cpm%20%5Cfrac%7B%5Csqrt%5B%5D%7B391%7Di%7D%7B4%7D)
Adding
both sides
![m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20%2B%20%5Cfrac%7B%5Csqrt%5B%5D%7B391%7Di%7D%7B4%7D)
This gives the two solutions
and
![m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20-%20%5Cfrac%7B%5Csqrt%5B%5D%7B391%7Di%7D%7B4%7D)
which becomes
and

Answer:
y=4x
Step-by-step explanation:
an independent variable is the variable that is changed or controlled in an experiment or observation to test the effects on the dependent variable
a dependent variable is variable being tested and measured in a scientific experiment
in this case, the number of help desk tickets closed out is dependent on the number of hours the individual works so y is the number of tickets closed (dependent variable). The number of tickets closed of will be 4 multiplied by the number of hours worked i.e. y=4x
Answer:3,570
Step-by-step explanation:you can use calculator lol
ANSWER

EXPLANATION
Coterminal angles are angles in standard position that have the same terminal side.
To find an angle in standard position that is coterminal with

We add or subtract multiples of

The first addition gives,

We add the second multiple to get,

Since this is the maximum value among the options, we end the addition here.
Let us now subtract the first multiple to get,

We end the subtraction here because this is the least value among the options.
Therefore the angles that are coterminal with

are