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1 answer:
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For the red line, we have:
gradient (
) = 1/3
y-intercept = 3
Equation of straight line is given by
, where is the gradient and 
is where the line intercept the y-axis
So we have,
The shaded part is above the line, hence the first inequality is
The black line, we have
gradient,
= 3
y-intercept = -2
, rearranging gives
The shaded region is to the right of the line, hence the inequality is
Note: The first option should be the correct answer but the inequality sign for <span>y > 1/3x + 3 should be </span>
gradient (
y-intercept = 3
Equation of straight line is given by
So we have,
The shaded part is above the line, hence the first inequality is
The black line, we have
gradient,
y-intercept = -2
The shaded region is to the right of the line, hence the inequality is
Note: The first option should be the correct answer but the inequality sign for <span>y > 1/3x + 3 should be </span>
Answer:
0 < 0.05, which means that we reject the null hypothesis, meaning that the air pressure of the balls is different of the target value of 7.9.
Step-by-step explanation:
The air pressure of a particular ball has a target value of 7.9 PSI.
This means that the null hypothesis is:
The alternate hypothesis is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
The hypothesis tested means that
Suppose the basketballs have a normal distribution with a standard deviation of 0.20 PSI.
This means that
When a shipment of basketballs arrive, the consumer takes a sample of 21 from the shipment and measures their PSI to see if it meets the target value, and finds the mean to be 7.3 PSI.
This means that
The test statistic is:
pvalue:
We are testing that the mean pressure is different than the target value of 7.9, and since the test statistic is negative, the pvalue is 2 multiplied by the pvalue of z = -13.74, which we find looking at the z-table.
has a pvalue of 0.
2*0 = 0
0 < 0.05, which means that we reject the null hypothesis, meaning that the air pressure of the balls is different of the target value of 7.9.