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Elza [17]
3 years ago
8

0.007 is 1/10 as much as

Mathematics
1 answer:
denis-greek [22]3 years ago
7 0
The answer is 0.07 hope it helps
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Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a
Nimfa-mama [501]

Answer:

Step-by-step explanation:

When Riko left his house, Yuto was 5.25 miles along the path.

Average speed of Riko = 0.35 miles per minute

Average speed of Yuto = 0.25 miles per minute

First we will calculate the time in which Riko will catch Yuto on the track.

Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto

= 0.35 - 0.25

= 0.10 miles per minute

Now we this relative velocity tells that Riko is moving and Yuto is in static position.

By the formula,

Average speed = \frac{Distance}{Time}

0.10 = \frac{5.25}{t}

t = \frac{5.25}{0.1}

t = 52.5 minutes

Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.

So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5

Here time can not be less than zero because time can not be with negative notation. It will always start from 0.

3 0
4 years ago
Read 2 more answers
25, 8, 10, 35, 5, 45, 40, 30, 20
Lera25 [3.4K]
B.) 37.5.. First you place all the numbers in order from least to greatest. Your mean is 25...and ur upper quartile because the 4 #'s fall even u add 35 and 40 and divide by 2... Which gives u upper quartile of 37.5 and lower quartile of 9. Hope this helps :)
4 0
3 years ago
Find the value of each trigonometric ratio. 18) cos X Y 24 24 25 24 A) C) 25 B) D) 24 25 25​
irina [24]

Answer:

Step-by-step explanation:

3 0
2 years ago
Solve each question for X , y=-9+x^2
aleksandrvk [35]
So basically you want to isolate only one of the variable on one side so
y=-9+x^2
add 9 to both sides
y+9=x^2
square root both sides
\sqrt{y+9}=x

x=\sqrt{y+9}
5 0
3 years ago
Read 2 more answers
How to solve this problem​
nevsk [136]

Let C be the center of the circle. The measure of arc VSU is 2+114x, so the measure of the minor arc VU is 360-(2+114x)=358-114x. The central angle VCU also has measure 358-114x.

Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so

m\angle VCU+2m\angle CUV=180

\implies m\angle CUV=\dfrac{180-(358-114x)}2=57x-89

UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so

(57x-89)+(31x+3)=90

\implies88x=176

\implies x=2

So finally,

m\widehat{VSU}=2+114\cdot2=230

degrees.

6 0
3 years ago
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