PLEASE HELP .!!! ILL GIVE BRAINLIEST.. EXRTA POINTS .. DONT SKIP :(( ! ILL GIVE 40 POINTS .

Mathematics

1 answer:

RSB [31]2 years ago

5 0

Answer:

x = 5

Step-by-step explanation:

11 = 4x-9

20 = 4x

20/4 = 4x/4

5 = x

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12/19*.............................= -12/19

melamori03 [73]

Answer:

$\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}$

Step-by-step explanation:

$\frac{12}{19} \times ..... = -\frac{12}{19}$

= $\frac{\frac{12}{19}}{-\frac{12}{19}}$

= $\frac{12}{19} \times -\frac{19}{12}$

= $-\frac{228}{228}$

= $\bold{-1}$

So, the appropriate value to complete it is -1

#CMIIW ^^

3 0

3 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

3 years ago

PLS HELP I DONT UNDERSTAND :( WILL GIVE BRAINLIEST !!!

vodomira [7]

the answer is c

i already done it

5 0

3 years ago

Read 2 more answers

I need help with this please !!!

n200080 [17]

Answer: It's Congruent but not similar because the shape on top doesn't look like the bottom left.