Answer:
the answer to this question is 52.18
Since each vector is a member of

, the vectors will span

if they form a basis for

, which requires that they be linearly independent of one another.
To show this, you have to establish that the only linear combination of the three vectors

that gives the zero vector

occurs for scalars

.

Solving this, you'll find that

, so the vectors are indeed linearly independent, thus forming a basis for

and therefore they must span

.
Answer:
option A
Step-by-step explanation:
The curve h(x)=-(x,-3)2 + 4 has a negative coeff for the degree e term. So the curve ud opened downward
To express the function in normal form,
H = -SQ(X) + 6X - 5
So the y intercept is -5
To find the roots of H
H = -SQ(X) + 6X - 5
(x-1)(x-5) = 0
so the curve has x intercept at 1 and 5
Thus the max point is at x=3
so the curve is shift right by 3 units
{ the function g(x)=x2 has turning point (0, 0) }
since the max point is at x=3, sub x=3 into the function H,
the max point is (3, 4)
So the function H is shift up by 4 unit