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zysi [14]
3 years ago
13

Find the X and Y intercept of line 2x+3y=-12 X-intercept - Y- Intercept-

Mathematics
1 answer:
vivado [14]3 years ago
7 0

Answer:

  • Let us rearrange
  • 3y=-2x-12
  • y=-2/3x-4
  • So y intercept is -4
  • I also do exams and quizzes if your interested :)
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2 45 is a common multiple of 5 and 9 true or false
Strike441 [17]

Answer:

False

Step-by-step explanation:

6 0
2 years ago
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Solve x^2+20x+100=50
uysha [10]
1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
 
 2. Pass the number 50 from the right member to the left member. Then you obtain:
 
 x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span> 
 3. Then, you must apply the quadratic equation, which is:
 
 x=(-b±√(b^2-4ac))/2a
 
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</span><span> 
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  4. Therefore, when you substitute the values into the quadratic equation and simplify ir, you obtain that the result is:
 
  -10</span>±5√2   (It is the last option).
6 0
3 years ago
6th grade math help me pleaseeee...
iren2701 [21]

Answer:

-3.8

Step-by-step explanation:

u = 3.8

u × -1 = 3.8 × -1

-u = -3.8

3 0
3 years ago
Identify the subsets of real numbers to which the number 25√ belongs.
Radda [10]
It would be rational
8 0
3 years ago
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What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)
andre [41]
<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

(4k + 159)^{\circ}

And another arc, let's call it FGH. measures:

(2k + 153)^{\circ}

If those arc are equal, then this equation is true:

(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3

Substituting k into the first equation:

\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}

3 0
3 years ago
Read 2 more answers
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