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kotykmax [81]
3 years ago
6

URGENT WILL GIVE BRAINLIEST PLZ HELP

Mathematics
1 answer:
Lorico [155]3 years ago
7 0

Answer:

22000

to the test

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Please help ** URGENT **brainiest for correct answer
gulaghasi [49]

Answer: 59

Step-by-step explanation:

The center angles are each 90, Each triangle adds to 180 and is the same as the other three that it forms the rhombus with. If the outside angles are 31 degrees then the last angle ( ADE ) must be 59 degrees

3 0
3 years ago
23/7y state restrictions
qwelly [4]

The restrictions on the variable of the given rational fraction is y ≠ 0.

<h3>The types of numbers.</h3>

In Mathematics, there are six (6) common types of numbers and these include the following:

  • <u>Natural (counting) numbers:</u> these include 1, 2, 3, 4, 5, 6, .....114, ....560.
  • <u>Whole numbers:</u> these comprises all natural numbers and 0.
  • <u>Integers:</u> these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.
  • <u>Irrational numbers:</u> these comprises non-terminating or non-repeating decimals.
  • <u>Real numbers:</u> these comprises both rational numbers and irrational numbers.
  • <u>Rational numbers:</u> these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.

This ultimately implies that, a rational fraction simply comprises a real number and it can be defined as a quotient which consist of two integers x and y.

<h3>What are restrictions?</h3>

In Mathematics, restrictions can be defined as all the real numbers that are not part of the domain because they produces a value of 0 in the denominator of a rational fraction.

In order to determine the restrictions for this rational fraction, we would equate the denominator to 0 and then solve:

23/7y;

7y = 0

y = 0/7

y ≠ 0.

Read more on restrictions here: brainly.com/question/10957518

#SPJ1

Complete Question:

State any restrictions on the variables 23/7y

4 0
2 years ago
Evaluate 252.7 - 19.​
earnstyle [38]

Answer: 233.7

Step-by-step explanation:

8 0
4 years ago
which function has real zeros at x = −10 and x = −6? f(x) = x2 16x 60 f(x) = x2 − 16x 60 f(x) = x2 4x 60 f(x) = x2 − 4x 60
LiRa [457]

Answer:

Option A is correct

The function x^2+16x+60 has real zeroes at x =-10 and x =-6

Explanation:

Given: The real zeroes or roots are x = -10, and x = -6

To find the quadratic function of degree 2.

x^2- (\alpha+\beta)x + \alpha\beta =0 where α,β are real roots.   ....[1]

Here, α= -10  and β= -6

Sum of the roots:

α+β =  -10+(-6) = -10-6 = -16

Product of the roots:

αβ = (-10)(-6)= 60

Substitute these value in equation [1] we have;

x^2-(-16)x+60 = x^2+16x+60

Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;

x^2+16x+60

8 0
3 years ago
Read 2 more answers
HELP QUICK I need to do this last question
yaroslaw [1]

Answer:

<u><em>45/49</em></u>

Step-by-step explanation:

You do the inverse operation so 7/15=15/7. 15/7×3/7= 45/49. You can't simplify it any further so it is 45/49.

3 0
3 years ago
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