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Marianna [84]
3 years ago
14

Rewrite the equation below so that it does not have fractions.

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

20x=-27 standard form or

20x+27=0 for implicit form

Step-by-step explanation:

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Two of the cards of an ordinary deck of 52 cards are lost. What is the probability that a random card drawn from this (defective
Nostrana [21]

Answer:

0.72

Step-by-step explanation:

Given :Two of the cards of an ordinary deck of 52 cards are lost.

To Find : What is the probability that a random card drawn from this (defective) deck is a spade?

Solution:

Total number of cards = 52

2 cards are lost

Remaining cards = 50

When no spade card is lost

So, No. of spade cards = 13

Total cards = 50

So, probability of getting spade = \frac{13}{50}

When 1 spade card is lost

So, No. of spade cards = 12

Total cards = 50

So, probability of getting spade = \frac{12}{50}

When 2 spade cards are lost

So, No. of spade cards = 11

Total cards = 50

So, probability of getting spade = \frac{11}{50}

So, The he probability that a random card drawn from this (defective) deck is a spade =  \frac{13}{50}+\frac{12}{50}+\frac{11}{50}

                  =  \frac{36}{50}

                  =  [tex]0.72/tex]

Hence the probability that a random card drawn from this (defective) deck is a spade is 0.72

3 0
3 years ago
30 points. Pls help if you can. Will mark brainliest!! I need how you got the answer pls <3 11) A box has Snickers, Milky Way
olga_2 [115]

Answer:

B is the answer

Step-by-step explanation:

Im the best

7 0
3 years ago
Uhm I'm confused and someone answer and explain it to me please? Thanks
zloy xaker [14]
The answer is 4/105

Explanation
6 0
3 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
4 years ago
I need help w this it’s gonna count as a test grade
Tanya [424]

Answer:

C

Step-by-step explanation:

< open circle, not ≤

6 0
3 years ago
Read 2 more answers
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