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AysviL [449]
2 years ago
11

Determine which postulate or theorem can be used to prove that APQS= ARQS. R P O A. SAS B. ASA O C. SSS D. AAS​

Mathematics
1 answer:
vodka [1.7K]2 years ago
3 0
I think it is A.SAS

I just learned this about a week ago so I apologize if it’s not correct
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Archaeology students are constructing a replica of the Great Pyramid of Giza that they will then fill with sand. The replica is
vichka [17]

Archaeology students are constructing a replica of the Great Pyramid of Giza that they will then fill with sand. The replica is to be 120the size of the original pyramid. The Great Pyramid is approximately 147 meters tall and each side of the base is approximately 230 meters long. Based on these measurements, how many cubic meters of sand will the students need? Round your answer to the nearest whole number.

Answer: 972 m^3 of sand

Step-by-step explanation:

Height of original pyramid = 147 meters

Each side of the base = 230 meters (that is both the base length and base width).

If replica pyramid is to be 1/20 the size of the original pyramid :

Size dimension of replica pyramid will therefore be,

Height = 1/20 × 147 = 7.35metres

Each Base = 1/20 × 230 = 11.5 metres

To calculate the amount of sand required, we can get these by Calculating the volume of the pyramid which us the amount of space occupied by an object.

The volume of a pyramid is given by:

(Base length × base width × height) ÷ 3

( 7.35 m × 11.5 m × 11.5 m) / 3

972.0375 m^3

That means the volume of the pyramid is 972.0375 m^3

4 0
3 years ago
To the nearest whole number, what is the surface area of a sphere with a volume of 140 cm3?
JulijaS [17]
We know that V= 4/3 pi r^3

So r^3= 140/ ((4/3) pi)= 33.422538

Hence r= 3.221166

SA = 4 pi r^2
= 4 pi 3.221166^2
= 130.39 cm^2
= 130 cm^2
6 0
3 years ago
Read 2 more answers
The distance S that a certain object falls from a height of 350 ft in T seconds is given by the following formula.
lubasha [3.4K]

Answer:

278 feet.

Step-by-step explanation:

S = 350 - 16t^2 + vt

t =2; v = -4.

S = 350 - 16 * (2)^2 + 2 * (-4)

S = 350 - 16 * 4 - 8

S = 350 - 64 - 8

S = 350 - 72

S = 278 feet.

Hope this helps!

4 0
2 years ago
Can someone please help me with math.
aleksklad [387]

Answer:

4: No

5: A

Step-by-step explanation:

4: The mapping does now represent a function. In a function each x value can only have 1 corresponding y value ( meaning that the x values can not repeat.) In the mapping the x value 3 corresponds with 2 y values therefore the mapping is not a function.

5.

Formula for volume of a cylinder = V=\pi r^2h

Where r = radius and h = height

The cylinder shown has a given diameter of 22ft and a given height of 10ft

In order to use the formula we must convert the diameter to radius.

To do this we divide the diameter by 2 ( this is because the radius is equal to half the diameter )

so radius = 22/2 = 11

Now we plug in the dimensions into the formula

V=\pi 11^210\\11^2=121\\121*10=1210\\1210\pi

Remember, it says " Leave your answer in terms of pi," therefore we do not apply pi and leave it as 1210π

We can conclude that the answer is A

6 0
3 years ago
URGENT! Describe step by step how to find the following equations.
yuradex [85]

Answer:

1. x = 45°

2. x = 330°

3. x = 105°

4. x = 30°

5. x = 60°

6. x = 30° or x = -45° (315°) or x = 45°

Step-by-step explanation:

1. For

cos x = sin x

∴ sin x/(cos x) = 1 = tan x

Hence, x = tan⁻¹1 = 45°

2. For

csc(x) + 3 = 1

∴ csc(x) = 1 - 3 = -2

Which gives sin x = -1/2

∴ x = sin⁻¹(-1/2) = -30° = 360 +(-30) = 330 °

3. For

cot(3x) = -1

∵ cot(3x) = 1/(tan(3x))

Hence, 1/(tan(3x)) = -1

∴ tan(3x) = -1

3·x = tan⁻¹(-1) = -45° = 360 + (-45) = 315°

Which gives, x = -45/3 = -15° or x = 105°

4. For

2·sin²(x) + 3·sin(x) = 2

We put sin(x) = y to get

2·y² + 3·y = 2 or 2·y² + 3·y - 2 =0

Factorizing gives

(2·y -1)(y+2) =0

∴ y = 1/2 or y = -2

That is, sin(x) = 1/2 or sin(x) = -2

Hence, x = sin⁻¹(1/2) = 30° or x = sin⁻¹(-2) = (-π/2 + 1.3·i)

∴ x = 30°

5. For

4cos²(x) = 3 we have;

cos²(x) = 3/4

cos(x) = √(3/4) = (√3)/2

∴ x = cos⁻¹((√3)/2) = 60°

6. For

4·sin³(x) + 1 = 2·sin²(x) + 2·sin(x)

We put sin(x) = y to get;

4·y³ + 1 = 2·y² + 2·y which gives;

4·y³ + 1 - (2·y² + 2·y) = 0 or 4·y³ -2·y² - 2·y + 1 = 0

Factorizing gives;

\frac{(2x-1)(2x+\sqrt{2}) )(2x-\sqrt{2})}{2} =0

Therefore, x = 1/2 or x = -(√2)/2 or (√2)/2

Therefore, sin(x) = 1/2 or -(√2)/2 or (√2)/2

That is x = sin⁻¹(1/2) = 30 or sin⁻¹(-(√2)/2) = -45 or sin⁻¹((√2)/2) = 45.

8 0
3 years ago
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