What is the measure of angle L?

ASAP<br><br> AND HOW DID YOU GET THE ANSWER<br><br> ( WILL MARK BRIANIST)

Luda [366]

Answer: 11/24

Convert 3/8 to 9/24

Convert 1/12 to 2/24

Add them together to get 11/24

If I did a poor job explaining I can help more in the comments.

3 0

3 years ago

Read 2 more answers

g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th

xxTIMURxx [149]

Answer:

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Sampling with replacement:

I consider a success choosing a black ball, so $p = \frac{50}{150+50} = \frac{50}{200} = 0.25$

We want 2 black balls and 2 white, 2 + 2 = 4, so $n = 4$ , and we want P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109$

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so $N = 200$

Sample of 4, so $n = 4$

50 are black, so $k = 50$

We want P(X = 2).

$P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116$

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

3 0

3 years ago

PLZ HELP WILL VOTE BRAINIEST

Ludmilka [50]

X + 1

Combine like terms, so terms with x go together and terms without an x go together

So 2x - x = x
3 - 2 = 1
That's as simplified as it can be

7 0

3 years ago

Find the probability of each event. A class has five boys and nine girls. If the teacher randomly picks six students, what is th

kumpel [21]

Answer: $\dfrac{60}{143}$

Step-by-step explanation:

Given, A class has five boys and nine girls.

Total students = 5+9=14

Number of ways to choose 6 students out of 14= $^{14}C_6$ [Using combinations]

Number of ways to choose 4 girls out of 6 (4 girls + 2 boys = 6 ) = $^{9}C_4\times\ ^{5}C_2$

If the teacher randomly picks six students, then the probability that he will pick exactly four girls:-

$\dfrac{^{9}C_4\times \ ^{5}C_2}{^{14}C_6}$

$=\dfrac{\dfrac{9!}{4!5!}\times\dfrac{5!}{2!3!}}{\dfrac{14!}{6!8!}}\\\\=\dfrac{1260}{3003}\\\\=\dfrac{60}{143}$

hence, the required probability = $\dfrac{60}{143}$ .

4 0

3 years ago

Evaluate. – 3 (–5) (2)

viktelen [127]

Answer: 30

Step-by-step explanation:

– 3 (–5) (2)

(15)(2)

30

4 0

2 years ago