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RUDIKE [14]
3 years ago
7

I need help! Idk what the answer is.

Mathematics
1 answer:
3241004551 [841]3 years ago
5 0
The answer is c -3 and 5
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There are 16 boys and 12 girls in mr..harts science class. He wants to form as many groups as possible for a project. All the gr
ser-zykov [4K]

Answer:

12

Step-by-step explanation:there are only 12 girls so that is the only amount of groups to be formed


5 0
3 years ago
I need help with my iCloud and I just started it
Mazyrski [523]

Answer:

m<U=60°

Step-by-step explanation:

\sin( sut) =  \frac{st}{ut}  \\  =  \frac{7 \sqrt{114} }{14 \sqrt{38} }  =  \\  \frac{ \sqrt{3} }{2}   \\  =  > u = 60

5 0
3 years ago
Jackie has a drawer with 20 buttons, each of different color. How many different ways can she choose three buttons for her bookb
prohojiy [21]
To find all the different possible combinations, you multiply all the possibilities for each position.

1st - she as 20 different possible buttons
2nd - she would have 19 possible buttons
3rd-she would have 18 possible buttons

20 x 19 x 18=6840 possible ways to choose these buttons.
5 0
4 years ago
A markup of 33% based on cost is desired for a load of 800 bushels of peanuts. They were purchased at $5.85 per bushel. What sho
Alenkasestr [34]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Number of bushels of peanuts = 800

Price of each bushels of peanuts = $5.85

And there is mark up rate = 33%

So, Total price would be

1.33\times 800\times 5.85\\\\=\$6224.4

If there is spoilage rate = 21%

So, the remaining rate would be 1-0.21=0.79

so, Number of remaining bushels of peanuts would be

0.79\times 800\\\\=632

So, Selling price per bushel would be

\dfrac{622.4}{632}\\\\=\$9.85

Hence, Option 'c' is correct.

4 0
3 years ago
Can you explain how to do this correctly?
iVinArrow [24]
8/x-7=7/2
16=7(x-7) cross multiply
16=7x-49
-7x=-49-16
-7x=-65 divides each side by -7
-7x/7=-65/7
X=65/7
Alternative form
X=92/7
Which is 1st options in your questions.

Hope this helps!
7 0
3 years ago
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