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RUDIKE [14]
2 years ago
7

I need help! Idk what the answer is.

Mathematics
1 answer:
3241004551 [841]2 years ago
5 0
The answer is c -3 and 5
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Eva is a kickboxing instructor who will be teaching classes at a local gym. To get certified as an instructor, she spent a total
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Answer:57+51+3

Step-by-step explanation: use https://www.cymath.com/

6 0
3 years ago
3(b + 8) = b + 48 PORFAVOR con plantamiento operacion y resultado, y de paso me explique el temas nsd9ucancuqna :( amaba matemat
ipn [44]

Answer:

b=12

Step-by-step explanation:

3b +24= b +48

       -24       -24

   3b =  b+ 24

   -b      -b

2b = 24

÷2     ÷2

b=12

5 0
3 years ago
Gap sells jeans that cost $21.00 for a selling price of $29.95. The percent of markup based on cost is
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If Gap sells jeans that cost $21.00 for selling price of $29.95. The percent of markup based on cost is approximately 43%. The markup in price is exactly $8.95.
3 0
3 years ago
Read 2 more answers
Marie spends $450.00 at a department store. She has two coupons: one for a 15% discount and one for $50 off any purchase above $
VMariaS [17]

Answer:

Her first coupon ti be used is $50 off a purchase above $300

Final purchase price= $340

Step-by-step explanation:

Marie has two coupons

one for a 15% discount and one for $50 off any purchase above $300.

The stores allow the two coupons to be combined and she spends a total of $450.

Her first coupon ti be used is $50 off a purchase above $300.

So Marie have $400 now

15% off $400= 400-(0.15*400)

15% off $400 = 400-60

15% off $400 =$ 340

6 0
2 years ago
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If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.
soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

x^2=a^2+b^2-2ab \cos(X)

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

11^2=4^2+8^2-2(4)(8)\cos(X)

121=16+64-64\cos(X)

121=80-64\cos(X)

Subtract 80 on both sides:

121-80=-64\cos(X)

41=-64\cos(X)

Divide both sides by -64:

\frac{41}{-64}=\cos(X)

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

\arccos(\frac{-41}{64})=X

Time for the calculator:

X=129.8 approximately

3 0
3 years ago
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