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Bumek [7]
3 years ago
5

Determine wether the given number is a solution of the given equation 10;4-8x=-69

Mathematics
2 answers:
I am Lyosha [343]3 years ago
5 0
No because if you subtract 4 from -69 it equals -73. then if you put -73 divided by -8 it equals positive 9.125.

Or if you put in 10 where the x is you would do 4-8 *10=-64
                                                                                 4-80=-69
                                                                                   -76=-69
otez555 [7]3 years ago
4 0
4 - 8x = - 69
-8x = -69 - 4
-8x = - 73
x = -73/-8
x = 9.125.....no, 10 is not a solution

or, instead of solving for x, we can just sub in 10 for x and see if it makes the equation true.

4 - 8x = -69
4 - 8(10) = -69
4 - 80 = -69
-76 = -69 (incorrect...therefore, it is not a solution)
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Which expression is equivalent to....​
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Answer:

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Step-by-step explanation:

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8 0
1 year ago
Read 2 more answers
1 point
swat32

Answer:

\log_{10}(147) = 2.1673

Step-by-step explanation:

Given

\log_{10} 3 = 0.4771

\log_{10} 5 = 0.6990

\log_{10} 7= 0.8451

\log_{10} 11 = 1.0414

Required

Evaluate \log_{10}(147)

Expand

\log_{10}(147) = \log_{10}(49 * 3)

Further expand

\log_{10}(147) = \log_{10}(7 * 7 * 3)

Apply product rule of logarithm

\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)

Substitute values for log(7) and log(3)

\log_{10}(147) = 0.8451 + 0.8451 + 0.4771

\log_{10}(147) = 2.1673

3 0
2 years ago
Solve the system by elimination <br> 2x+6y= -12 <br> 5x-5y= -10
kvv77 [185]
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
       4y  = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2


Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

5 0
3 years ago
Read 2 more answers
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