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harkovskaia [24]
3 years ago
11

A jacket at a clothing store is being discounted by 10%. If the jacket was originally priced at x dollars, which of the followin

g expressions does NOT represent the final price of the jacket before sales tax is added?
A.0.90x
B.x – 0.10x
C.x – 1.10x
D.x(1 – 0.10)
Mathematics
2 answers:
ololo11 [35]3 years ago
5 0

Answer: I'm pretty sure its answer D

r-ruslan [8.4K]3 years ago
4 0

Answer:a

Step-by-step explanation:

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1,000.00 at 4.5% interest for 2 years
siniylev [52]
Each year we add 4.5% interest.
4.5% as a decimal is 0.045.
We multiply by 1.045 to add this interest.
(not 0.045, this would just be the interest and wouldn't keep the whole)

To start: $1,000
Multiply by 1.045 for the first year.
Now we have $1,045.
Multiply by 1.045 again for the second year.
Now we're at 1092.025.
We need to round up to the nearest cent...$1,092.03
4 0
3 years ago
"flower, heart, circle." what is The 35th shape is
kramer

Answer:

heart

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
Someone please help me??
lapo4ka [179]
The standard equation of a circle with centre (xc,yc) and radius R is given by

(x-x_c)^2+(y-y_c)^2=R^2

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore

(x-x_c)^2+(y-y_c)^2=R^2
(x-4)^2+(y-(-3))^2=2.5^2
(x-4)^2+(y+3)^2=2.5^2  or
(x-4)^2+(y+3)^2=6.25
7 0
3 years ago
Is (x-2) a factor of f(x) = (4x +13x +10)?
Inessa [10]

Answer:

Step-by-step explanation:

No but it is close.   (4x +13x +10) factors into

(4x + 5)(x + 2)

So (x + 2) is a factor along with (4x + 5)

3 0
3 years ago
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