Each year we add 4.5% interest.
4.5% as a decimal is 0.045.
We multiply by 1.045 to add this interest.
(not 0.045, this would just be the interest and wouldn't keep the whole)
To start: $1,000
Multiply by 1.045 for the first year.
Now we have $1,045.
Multiply by 1.045 again for the second year.
Now we're at 1092.025.
We need to round up to the nearest cent...$1,092.03
Answer:
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Step-by-step explanation:
Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
The standard equation of a circle with centre (xc,yc) and radius R is given by

Substituting
centre (xc,yc) = (4,-3)
R=2.5
The equation is therefore



or
(x-4)^2+(y+3)^2=6.25
Answer:
Step-by-step explanation:
No but it is close. (4x +13x +10) factors into
(4x + 5)(x + 2)
So (x + 2) is a factor along with (4x + 5)