-236 = -3b – 5(1 +6b)

How do I solve (350^9/350^5)?

Snezhnost [94]

Answer:

350^4.

Step-by-step explanation:

When dividing the same base by different exponents, subtract the exponents.

8 0

3 years ago

Plz help it’s due tonight!!!

jasenka [17]

sorry

Step-by-step explanation:

4 0

3 years ago

A baker uses 131 2 cups of flour to make key lime bread. She uses 21 4 cups of flour to make each loaf. The baker sells 2 3 of t

elena-14-01-66 [18.8K]

Answer:

She sells 4 loaves of key lime bread

Step-by-step explanation:

Extracting the key information from the question:

*** A baker uses 13 1/2 cups of flour to make key lime bread

*** She uses 2 1/4 cups to make each loaf.

*** She sells 2/3 of the loaves of bread that she makes.

Now, since she uses 2 1/4 to make each loaf, we will convert this into improper fraction.

2 1/4 = [(4×2)+1]/4 = 9/4

She uses a total of 13 1/2 cups of flour to make all loaves.

To find the number of loaves she makes, we will divide the overall quantity of flour used by the quantity used to make a loaf

13 1/2 ÷ 2 1/4

Since 13 1/2 and 2 1/4 are the same as 27/2 and 9/4 respectively (mixed to improper fractions), we will then divide 27/2 by 9/4

= 27/2 × 4/9 = 6 loaves (total bread she makes).

Again, we learnt she sells 2/3 of the total loaves she makes.

Since total = 6, then 2/3 of 6 is:

2/3 × 6 = 4 loaves .

Therefore, the baker sells 4 loaves of key lime bread.

5 0

4 years ago

Read 2 more answers

In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat

Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

427 had paid for coaching courses and the remaining 2733 had not.

This means that $n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147$

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0

3 years ago

in a 10 team league, each teams play every other team exactly twice. find the total number of games played in the league

LuckyWell [14K]

Since it’s a 10 team league and each team plays with the other team twice then 10+10=20, thus there would be 20 games played

7 0

3 years ago