10.022 in word form
2 answers:
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Hey there!
To plot the inequality y≥-6 on the coordinate plane, keep in mind that whenever you have y set equal to a constant, your graph will be a horizontal line. Therefore, your graph would be a solid (not dashed since your sign is greater than or equal to) horizontal line passing through (0,-6). Then you would shade the portion over the line to signify that the values of y must be greater than or equal to -6.
The graph below shows y≥-6:
To plot the inequality y≥-6 on the coordinate plane, keep in mind that whenever you have y set equal to a constant, your graph will be a horizontal line. Therefore, your graph would be a solid (not dashed since your sign is greater than or equal to) horizontal line passing through (0,-6). Then you would shade the portion over the line to signify that the values of y must be greater than or equal to -6.
The graph below shows y≥-6:
To find the equation, for the x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, –16) we have to find the nature of the curve.
The correct option is f(x) = –2(x – 2)(x – 4).
Given:
The x-intercepts at (2, 0) and (4, 0).
The y-intercept of (0, –16).
The nature of the graph is quadratic curve. Write the general equation for x-intercept.
Where is number
Substitute 0 for .
We have y-intercept of (0, –16).
The equation would be,
Thus, the correct option is f(x) = –2(x – 2)(x – 4).
Learn more about equitation here: