(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Answer:
n= 5.57 years
Step-by-step explanation:
Giving the following information:
your final balance on an investment of 270$ invested at 10% was $459.00
<u>To calculate the time passed between values, we need to use the following formula:</u>
n= ln(FV/PV) / ln(1+i)
FV= 459
PV= 270
i= 0.1
n= ln(459/270) / ln (1.1)
n= 5.57 years
Answer:
9,556
Step-by-step explanation:
Answer:
25/40=13/20
Step-by-step explanation:
just add 9 and 17 which is 26. so it's 26/40. simplify so it's 13/20
