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3 years ago

What is the sequence steps of finding the median?

1 answer:

mote1985 [20]3 years ago

5 0

Step 1: Put the numbers in numerical order from smallest to largest. Step 2: If there is an odd number of numbers, locate the middle number so that there is an equal number of values to the left and to the right.

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A class consists of 8 freshman and 22 sophomores.Freshman had an average of x points on a test,while sophomores had an average o

nirvana33 [79]

It's C because you need to find how many points each student earned per grade (freshman & sophomore). Then you multiply it by 30 to find out how many points each student scored in the whole class.

Hope this helps!

3 0

3 years ago

-4y + 4 = -2(6x - 2)

Katena32 [7]

Answer:

y= -5

Step-by-step explanation:

5 0

3 years ago

Calculate the rise and run between any two coordinates to find the slope of each line ...

NISA [10]

For the first one its a slope of -2/3

The second one is 4/5

and the third one is -1/7

3 0

2 years ago

It is 185 miles to Fort Worth. If Vang drives

astra-53 [7]

2 hour at 65 mile per hour

65 x 2 = 130

130 miles driven within those 2 hours

185 - 130 = 55

Vang is 55 miles away from Fort Worth

hope this helps

4 0

3 years ago

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago