It’s the first graph or A
Answer:54.117
Step-by-step explanation:
Mean=45.4
Standard deviation=5.3
=5%. =0.05
1-0.05=0.95
Normal Dist(40,10)
InverseCdf(0.95,45.4,5.3)
Answer:
70 seconds
Step-by-step explanation:
Given that;
The initial velocity
of the bullet fired = 1120 ft/s
Initial height h = 8 feet
The expression to determine how many seconds it takes the bullet to hit the ground is:

Thus;
Replacing the value of
= 1120 and h = 0 (i.e. when h =0) in the above expression; we have:


= -16t² + 1120t + 8
mulitiply through by (-)
= 16t² -1120t - 8
Divide through by 8
= 2t² - 140t - 1
The above expression forms a quadratic equation.
where;
a = 2
b = -140
c = - 1
So, by using the quadratic formula
, we have:






= 70
Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds
C) 30 * IQR is the box. So the highest point on the box is 95 and the lowest is 65, which makes the difference 30. I hope this helped!!