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3 years ago

The tables represent linear relationships. Determine if each relationship is a

Mathematics

1 answer:

Mila [183]3 years ago

3 0

Answer:

5. proportional

6. nonproportional

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Simplify √ a^7 , where a>0 Which expression is equivalent to √a^7

Softa [21]

Answer:

$a^{3} \sqrt[]{a}$

Step-by-step explanation:

8 0

3 years ago

So the people who are good at math Im going to ask 17 questions that invlove math so if u want 20 points in each question then g

PilotLPTM [1.2K]

Answer: ok will do

Step by step explanation

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2 years ago

What is the vertex of g(x) = 3x2 − 12x + 7? (−6, −5) (−2, −5) (2, −5) (6, −5)

34kurt

Answer:

(2, -5)

Step-by-step explanation:

Convert to vertex form:

3x^2 - 12x + 7

= 3(x^2 - 4x) + 7

Completing the square:

= 3[ (x - 2)^2 - 4)] + 7

= 3(x - 2)^2 - 12 + 7

= 3(x - 2)^2 - 5.

Comparing with the general form

a(x - b)^2 + c we see that the vertex is (b, c) = (2, -5).

4 0

2 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

Please Help Me I Only Have 30 Minutes Left

iVinArrow [24]

I pretty sure it’s B

6 0

3 years ago