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2 years ago

Could someone help me solve this math problem, please? Thanks!

Mathematics

2 answers:

kap26 [50]2 years ago

6 0

We can write the factored form of the equation because we know the roots are 3 and 5.
Therefore the factored form is (x-3)(x-5) Remember it is -3 and -5 because of the Zero Product Property.
From here, we can foil. (x-3)(x-5)=x^2-5x-3x+15
That simplifies to x^2-8x+15, which is choice B

bearhunter [10]2 years ago

5 0

Use vertex form
y=a(x-h)²+k
(h,k) is the vertex
a is some number

so
we see the verttex is at (4,-1)
so
h=4 and k=-1
y=a(x-4)²-1

find a

use a point
(3,0)
x=3 and y=0
0=a(3-4)²-1
0=a(-1)²-1
0=a-1
1=a

so da equation is
y=1(x-4)²-1
expanded we get
y=x²-8x+16-1 or
y=x²-8x+15

so that would be B

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melisa1 [442]

Answer:

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Step-by-step explanation:

8 0

2 years ago

Lester orders a book for $35. He must pay a shipping charge of 12%. Show how to find 12% of $35 by using benchmark percents, the

Elis [28]

Answer:

$4.2

Step-by-step explanation:

1. 12%=0.12

2. 0.12 of $35 = 0.12 × $35

3. = $4.2

8 0

2 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

3 years ago

Determine whether the triangle is a scalene, isosceles of equilateral

Phoenix [80]

Answer:

Equilateral triangle: All three sides are equal.

Isosceles triangle: All two sides are equal.

Scalene triangle: No sides are equal.

Step-by-step explanation: Step 1: Label the given points as A, B, and C, and plot them as vertices of a triangle with connecting lines to draw the triangle we are working to identify.

Step 2: Calculate the side length AB using the distance formula.

Step 3: Calculate the side length BC using the distance formula.

Step 4: Calculate the side length AC using the distance formula.

Step 5: Compare the side lengths AB, BC, and AC from the previous steps to define the triangle type.

4 0

2 years ago

A high school holds a charity raffle every year that awards a randomly chosen student a small gift certificate to a local mall.

hichkok12 [17]

Answer:

Neither of the two groups of students is right.

Step-by-step explanation:

If the probability that Jessica will win the raffle this year was $x$ , the probability that she will win the raffle in subsequent years is $x$ given that the number of students do not change. Since this is a random win, she as likely to win next year as she was this year.

Another way to explain this is to say that the probability of Jessica winning the raffle this year is independent of the probability that she wins the raffle next year. Suppose event A, is the event that Jessica wins the raffle this year, let event B be the event that she wins the raffle next year, event A and B are independent because the occurrence of event A does not affect the occurrence of event B in any way

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3 years ago